Question

What is the value of c such that x^2-20x+c is a perfect-square trinomial?

Answer 1

Answer:

100

Step-by-step explanation:

The question is on making the equation a perfect square

Given ;

$x^2 - 20x + c$

To get c;

$c=(\frac{b}{2} )^2$

where ;

$b= -20$

$c= (\frac{-20}{2} )^2 = 10^2 = 100$

Answer 2

Answer:

c=100

Step-by-step explanation:

To complete the square, it would really help if the coefficient of x^2 is 1 which is so formula for c in this case is just (b/2)^2

So (-20/2)^2

simplifying gives

(-10)^2

100

c=100