<span>13.2 gallons=49.9 liters
the gas is the octan C8H18
the combustion of Octan equation is
C8H18 + 25/2 O2-------------------> 8CO2 + 9 H2O
1mole 8 moles
n(C8H18)=a n(CO2)=b
so
1 mole/a = 8moles /b
and b= 8molesx a
we must find the value of a, molar volume of a gas is v= 22.4l/mol=V/a, so a=V/v= 49.9/22.4= 2.23 moles
and b=8 x a=8x 2.23=17.85 moles
M(CO2)=m(CO2)/n(CO2)====> m=n x M=17.85 * (12+2x16)= 785.4 g
m(CO2)=785.4g = 1.57 pound</span>
Answer:
p=-7 :)
Step-by-step explanation:
-13-8=3p
-13+(-8)=3p
-21=3p
÷3
-7=p
Answer:
d
Step-by-step explanation:
Answer:
550
Step-by-step explanation:
so we know that 17% of everyone who applies (3,240) will be accepted.
0.17*3,240= 550.8
550 students will be accepted
we have to round down as only 17% can be accepted and u cant have 0.8th of a person
hope this helps
aera=pi*radius^2
diameter/2=radius
given tat diameter=15
iameter/2=15/2=7.5=radius
area=pi*radius^2=3.14*7.5^2=3.14*7.5*7.5=176.625 in^2
so answer is D
