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goldfiish [28.3K]
3 years ago
14

If g(x) = 1 - ¾ x find: -5g(4) - 1

Mathematics
2 answers:
cricket20 [7]3 years ago
5 0

Answer:

<u>-</u><u>5</u><u>g</u><u>(</u><u>4</u><u>)</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>is</u><u> </u><u>9</u>

Step-by-step explanation:

g(x) = 1 -  \frac{3}{4} x

when x is 4:

g(4) = 1 -  \frac{3}{4}  \times 4 \\  = 1 - 3 \\  =  - 2

therefore:

- 5g(4) - 1 =  - 5( - 2) - 1 \\  = 10 - 1 \\  = 9

sukhopar [10]3 years ago
4 0

Answer:

9

Step-by-step explanation:

g(x) = 1 - ¾ x

-5g(4) - 1

First find g(4) = 1 - 3/4(4) = 1 - 3 = -2

Then -5(-2) -1 = 10 -1 = 9

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Answer:

5 x − 2 y = 6

Step-by-step explanation:

<em>Hope this helps :)</em>

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Step-by-step explanation:

6m+15n-12p/n where m=-3.5, n=4 and p=3

6(-3.5)+15(4)-12(3)/4=-21+60-36/4

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What fraction of $1.00 is $0.40?
Irina18 [472]
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4 0
3 years ago
Read 2 more answers
1. f(x) = 2x + 4 when x = 5
Dmitriy789 [7]

Answer:

f(5)=14

Step-by-step explanation:

f(5)=2(5)+4

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3 0
3 years ago
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Find the average value of f(x, y = over the region, r, the triangle with vertices (0, 0, (0, 1 and (1, 1.
makkiz [27]
Can't be done without knowing what f is...

But I can tell you that the average value of f is given by

\dfrac{\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_R\mathrm dx\,\mathrm dy}

At the very least, we can compute the denominator, which is just the area of R. You have

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so the average value will be

2\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy
4 0
4 years ago
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