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Misha Larkins [42]

1 year ago

7

A center pivot irrigation system provides water to a sector shaped field, find the area of the field if 0=140 degrees and r= 40

yd

1 answer:

Anastasy [175]1 year ago

4 0

The area of the sector is approximately 1954.77 square yards.

A circular sector, also known as a circle sector or a disc sector (symbol:), is a piece of a disc (a closed region bordered by a circle) encompassed by two radii and an arc. The smaller area is known as the minor sector, and the bigger is known as the major sector.

Any point on the circle outside of the sector can be connected to the arc's endpoints to produce half of the central angle.

We know that the area of a circle is πr² and the area of the sector of a circle with angle θ is given by θ/360 πr² .

Area of the sector

= 140°/360° × π × 40²

= 1954.7687... square yards.

≈ 1954.77 square yards.

Therefore the area of the sector is approximately 1452.113 square yards.

To learn more about sector visit:

brainly.com/question/16989821

#SPJ1

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A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop

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Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

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n is the number of objects
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In this case

n₁ is the identical copies of Hamlet
n₂ is the identical copies of Macbeth
n₃ is the identical copies of Romeo and Juliet
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Therefore,

<em>Number of distinct arrangements = 10!/(4! × 3! × 2! × 1!)</em>

<em> = </em><em>12600 ways</em>

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Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

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3 years ago

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Answer:

21. The slope is 50.

22. 0

23. y=50x

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Step-by-step explanation:

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In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph

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Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

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Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

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$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

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Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

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