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3 years ago

State weather ADB~CDB, and if so , explain how you know

Mathematics

1 answer:

algol133 years ago

7 0

Answer:

SAS

Step-by-step explanation:

AD = DC Given

<ADB = <CDB Givien

BD = BD Reflexive property.

The angle is between the 2 sides. The triangles are congruent by SAS.

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What is the answer to 16-2t = t + 9 + 4t I need it now

bogdanovich [222]

16 - 2t = t + 9 + 4t

16 - 2t = 5t + 9

-7t = -7

t = 1

Hope this helps! ;)

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3 years ago

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Find the angle between the given vector in degrees. u=<6, 4>, v=<7, 5> HELPPPPPPPPPP

Paladinen [302]

Recall that

$\vec a\cdot\vec b=\|\vec a\|\|\vec b\|\cos\theta$

where $\theta$ is the angle between the vectors $\vec a,\vec b$ whose magnitudes are $\|\vec a\|,\|\vec b\|$ , respectively.

We have

$\langle6,4\rangle\cdot\langle7,5\rangle=\sqrt{6^2+4^2}\sqrt{7^2+5^2}\cos\theta$

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2 years ago

Kelly needs $125 to buy a dress for the dance. Her dad gave her five dollars for doing your chores and received $15 an hour to t

Debora [2.8K]

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3 years ago

Find the value of x when 6 - 4x = 6x - 8x + 12

seraphim [82]

Answer:

x = -3

Step-by-step explanation:

Step 1: Write out equation

6 - 4x = 6x - 8x + 12

Step 2: Combine like terms (x)

6 - 4x = -2x + 12

Step 3: Add 4x on both sides

6 = 2x + 12

Step 4: Subtract 12 on both sides

-6 = 2x

Step 5: Divide both sides by 2

-3 = x

Step 6: Rewrite

x = -3

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3 years ago

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What is the sum? StartFraction 3 y Over y squared + 7 y + 10 EndFraction + StartFraction 2 Over y + 2 EndFraction

katovenus [111]

Answer:

$\dfrac{5}{y+5}$

Step-by-step explanation:

Here, we have to find the sum of 2 fractions:

1st fraction: $\dfrac{3y}{y^{2}+7y+10}$

2nd fraction: $\dfrac{2}{y+2}$

Considering the denominator of 1st fraction:

$y^{2}+7y+10$

Using factorization method:

$7y$ can be written as $(2y + 5y)$ .

$\Rightarrow y^{2}+2y+5y+10$

Taking 5 common from $5y+10$ and y common from $y^{2}+2y$ : $\Rightarrow y(y+2)+5(y+2)$

Now taking $(y+2)$ common:

$\Rightarrow (y+5)(y+2)$

$\dfrac{3y}{y^{2}+7y+10}$ can be written as $\dfrac{3y}{(y+5)(y+2)}$

Now, calculating the sum:

$\dfrac{2y}{(y+5)(y+2)} + \dfrac{2}{y+2}$

Taking LCM and solving:

$\Rightarrow \dfrac{3y+2(y+5)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5y+10}{(y+5)(y+2)}\\\Rightarrow \dfrac{5(y+2)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5}{(y+5)}$

Hence, answer is $\dfrac{5}{y+5}$ .

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3 years ago