Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
The answer is x+8.
Because you gotta factor out first and then cancel.
I'm pretty sure the answer is checking account A. Hope this helps
Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
We will be using simultaneous equations to solve this problem.
First we will establish the equations which we will be using as displayed below:
Equation No. 1 -
A + B = 90°
Equation No. 1 -
A = 2B + 12
To begin with, let's make ( A ) the subject in the first equation as displayed below:
Equation No. 1 -
A + B = 90
A = 90 - B
Next we will substitute the value of ( A ) from the first equation into the second equation and solve for ( B ) as displayed below:
Equation No. 2 -
A = 2B + 12
( 90 - B ) = 2B + 12
- B - 2B = 12 - 90
- 3B = - 78
B = - 78 / - 3
B = 26°
Then we will substitute the value of ( B ) from the second equation into the first equation to solve for ( A ) as displayed below:
A = 90 - B
A = 90 - ( 26 )
A = 64°
ANSWER:
Therefore, the answer is:
A = 64°
B = 26°
Please mark as brainliest if you found this helpful! :)
Thank you <3
