Answer:
Step-by-step explanation:
E(-1,6) & F(-2,-10)
![Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\ \ \ \ = \frac{-10-6}{-2-[-1]}\\](https://tex.z-dn.net/?f=Slope%20%3D%20%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D%5C%5C%5C%5C%5C%20%20%5C%20%20%5C%20%5C%20%3D%20%5Cfrac%7B-10-6%7D%7B-2-%5B-1%5D%7D%5C%5C)

Slope of the line perpendicular to this line = -1/m = -1/16
The area of a cross section paralell to the base is the base
the base is 4inches by 3 inches
area is 12 square inches
perimiter is 2(L+W)=2(4+3)=2(7)=14 inches
area is 12 square inches
perimiter is 14 inches
3x - y = 2
y = 2x - 9
Substitute:
3x - 2x - 9 = 2
x - 9 = 2
x = 11
Substitute your answer into any equation:
y = 2x - 9
y = 2(11) - 9
y = 22 - 9
y = 13
Answer:
x = 11 ; y = 13
Answer:
0.15 or 15%
Step-by-step explanation:
Since lengths are uniformly distributed, the probability that a class period runs between a two exact times is:

In this case, a = 47.0 and b = 52.0 minutes.
The probability that a given class period runs between 50.25 and 51.0 minutes is:

The probability is 0.15 or 15%.
here is your answer my friend.






