Answer:
The value of x is 4.
Step-by-step explanation:
Given:
Let B be between A and C.
To Find:
x=?
Solution:
B be between A and C as shown in Figure
A-B-C such that
...........Line Addition Property
Substituting the given values we get
The value of x is 4.
Answer: We are 95% confident that the mean SPF level of sunscreen used by all Cal Poly students is between 29.0813 and 40.0187.
Step-by-step explanation:
Given : Significance level :
Sample size : n= 52 , which is a large sample (n>30), so we use z-test.
By using z-value table,
Critical value:
Sample mean :
Standard deviation :
The confidence interval for population means is given by :-
i.e.
Now, the 95% confidence interval for the ppopulation mean = . (29.0813, 40.0187)
Hence, We are 95% confident that the mean SPF level of sunscreen used by all Cal Poly students is between 29.0813 and 40.0187.
Since the word, 'of' means to multiply, whenever we see of multply the two numbers.
Then there are two ways to dothis, sicne to convert a percentage into a decimal, you devide by 100, we can either do this after we multiply or bfore, it doesn't matter so I'm going to do it after.
1. 520x100=52000/100=520
2. 20.25x3=60.75/100=.6075
3. .15x250=37.5/100=.375
4. 200x79=15800/100=158
5..3x80=24/100=.24
6. .28x50=14/100=.14
Answer:
Step-by-step explanation:
x² + 6x + 9 = 12 → x² + 6x - 3
Since this Quadratic Expression is unfactorable, apply the <em>Quadratic</em><em> </em><em>Formula</em>:
√48 = √[3 × 16] = 4√3
½[4√3] = 2√3
Then attach half of -6 to it as well [-3]:
-3 ± 2√3
I am joyous to assist you anytime.
Answer:
56.39 nm
Step-by-step explanation:
In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,
where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...
Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.
In order to have its longest constructive reflection at the red end (700 nm)
Here we take m=0.
Similarly for the constructive reflection at the blue end (400 nm)
Hence the thickness difference should be