First, reflect the triangle across x
Then translate the triangle 1 unit to the right and 9 units down
a) ∠PQR=65° (alternate interior angles theorem)
∠PRQ = 60° (linear pair)
x = 55° (angles in a triangle add to 180°)
b) ∠APQ and ∠PQR are congruent alternate interior angles.
$3.13 is the answer like it please thanks
X² - 14x + 33 = 0 is in the form ax² + bx + c = 0. We will need this for the second step.
Subtract 33 from both sides
x² - 14x = - 33
Divide the b term by 2 and then square the result. Then add that to both sides.
- 14 / 2 is - 7. (- 7)² = 49. Add that to both sides
x² - 14x + 49 = - 33 + 49
Combine the constants and factor the trinomial
(x - 7)² = 16
Square root both sides
x - 7 = +/- 4
or
x - 7 = - 4 and x - 7 = 4
You have to place a plus-minus statement because (- 4)² and 4² both equal 16.
Now we solve for x in each equation. Add 7 to both sides to isolate our variable.
x = 3 and x = 11
