Question

What is the slope of a line perpendicular to the line passing through E(-1,6) and F(-2,-10)?

Answer 1

Answer:

Step-by-step explanation:

E(-1,6)  & F(-2,-10)

$Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\ \ \ \ = \frac{-10-6}{-2-[-1]}$

$=\frac{-10-6}{-2+1}\\\\=\frac{-16}{-1}\\\\= 16$

Slope of the line perpendicular to this line = -1/m =  -1/16