What is the slope of a line perpendicular to the line passing through E(-1,6) and F(-2,-10)?

Mathematics

1 answer:

STatiana [176]1 year ago

7 0

Answer:

Step-by-step explanation:

E(-1,6) & F(-2,-10)

$Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\ \ \ \ = \frac{-10-6}{-2-[-1]}\\$

$=\frac{-10-6}{-2+1}\\\\=\frac{-16}{-1}\\\\= 16$

Slope of the line perpendicular to this line = -1/m = -1/16

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