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Montano1993 [528]
3 years ago
10

Twenty percent of cars that are inspected have faulty pollution control systems. The cost of repairing a pollution control syste

m exceeds $100 about 40% of the time. When a driver takes her car in for inspection, what’s the probability that she will end up paying more than $100 to repair the pollution control system?
Mathematics
1 answer:
gulaghasi [49]3 years ago
4 0

Answer:

8%

Step-by-step explanation:

Assumption: her car has faulty pollution control system is independent of the cost of repairing a pollution control system exceeds $100.

Applying the multiplication rule gives:

faulty pollution control system and cost of repairing it exceeds $100 = 0.2*0.4 = 0.08 = 8%

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DerKrebs [107]

Answer:

a) The probability that this whole shipment will be​ accepted is 30%.

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Step-by-step explanation:

We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.

We select a sample of size 48 and test for defectives.

If more than one aspirin is defective, the batch is rejected.

The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48

We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

P(X\leq1)=P(X=0)+P(X=1)\\\\\\P(0)=\binom{48}{0}(0.05)^0(0.95)^{48}=1*1*0.0853=0.0853\\\\\\P(1)=\binom{48}{1}(0.05)^1(0.95)^{47}=48*0.05*0.0897=0.2154\\\\\\P(X\eq1)=0.0853+0.2154=0.3007

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3 years ago
2 Two of the angles of this polygon are 100°. All the other angles are equal. (100° 1000 Calculate the size of the unmarked angl
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3 years ago
Could someone please explain to me how to do this!
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Ohhhh, I did this stuff last year. i wish i can remember... but your best bet is A because that angle is super small so A would be best. Hope I helped brainliest plz

6 0
3 years ago
What’s the x on this triangle ?
Dmitry [639]

Answer:

x = 5

Step-by-step explanation:

x is the length of the hypotenuse of this triangle.  The length of one of the legs of the triangle is 3" and that of the other leg is 4".

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2 years ago
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