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Montano1993 [528]
2 years ago
10

Twenty percent of cars that are inspected have faulty pollution control systems. The cost of repairing a pollution control syste

m exceeds $100 about 40% of the time. When a driver takes her car in for inspection, what’s the probability that she will end up paying more than $100 to repair the pollution control system?
Mathematics
1 answer:
gulaghasi [49]2 years ago
4 0

Answer:

8%

Step-by-step explanation:

Assumption: her car has faulty pollution control system is independent of the cost of repairing a pollution control system exceeds $100.

Applying the multiplication rule gives:

faulty pollution control system and cost of repairing it exceeds $100 = 0.2*0.4 = 0.08 = 8%

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Andrew [12]
Part 1
We are given x^2-21x=-4x. This can be rewritten as x^2-18x=0.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
     x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}
     x=\frac{18\pm 18}{2}

The values of x are
     x_1=\frac{18-18}{2}=0
     x_2=\frac{18+18}{2}=18

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function. 

Part 3.
The first equation is y=x^2+2.
The second equation is y=3x+20.

We have 
     x^2+2=3x+20
     x^2-3x-18=0
Factoring, we have 
     \left(x-6\right)\left(x+3\right)=0
Equating both factors to zero.
     x_1-6=0\rightarrow x_1=6
     x_2+3=0\rightarrow x_2=-3

When the value of x is 6, the value of y is 
     y=3\left(6\right)+20=38

When the value of x is -3, the value of y is 
     y=3\left(-3\right)+20=11

Therefore, the solutions are (6,38) or (-3,11)
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Step-by-step explanation:

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Shtirlitz [24]
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6 0
3 years ago
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(Congruent polygons)
olasank [31]
1. is line FG
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7 0
2 years ago
What is the correct answer and why show your work
Anna11 [10]

Answer:

A7.45x = y

Step-by-step explanation:


We can use a ratio to solve this problem.  Take the total cost of the lunches and divide by the number of lunches.

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