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myrzilka [38]
2 years ago
11

Having issues with solving this

Mathematics
1 answer:
Vadim26 [7]2 years ago
3 0

By applying the concept of <em>finite</em> sum and the properties of the series, we conclude that the <em>finite</em> sum p = \sum \limit_{x=1}^{3} 2^{x}+ 2 is equal to the value of 34.

<h3>How to find the result of finite sum</h3>

Let be a sum of the form p = \sum\limits_{i= 1}^{n} a_{i}, where n represents an integer. This kind of sum represents a <em>finite</em> sum, whose <em>expanded</em> form is presented below:

p = a₁ + (a₁ + a₂) + (a₁ + a₂ + a₃) + ... + (a₁ + a₂ + a₃ + ... + aₙ₋₁ + aₙ)     (1)

If we know that p = \sum \limit_{x=1}^{3} 2^{x}+ 2, then the result of the finite sum is:

p = (2 + 2¹) + (2 · 2 + 2¹ + 2²) + (3 · 2 + 2¹ + 2² + 2³)

p = 4 + (4 + 6) + (6 + 14)

p = 4 + 10 + 20

p = 34

By applying the concept of <em>finite</em> sum and the properties of the series, we conclude that the <em>finite</em> sum p = \sum \limit_{x=1}^{3} 2^{x}+ 2 is equal to the value of 34.

To learn more on series: brainly.com/question/15415793

#SPJ1

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<h2>Question:- Area of the given diagram</h2>

<h2>Answer :- </h2>

Divide the diagram as shown in attachment.

Now first calculate the area of the rectangle having side 1 and 12

So area = length ×breadth

Area = 1× 12 = 12 unit²

Now find the Area of the remaining triangle with sides 12,13,5 units

So

Area =  \frac{1}{2}  \times base  \times height \:

Now put the value as -> base= 5 and height= 12

Area =  \frac{1}{2}  \times base  \times height \:  \\ Area =  \frac{1}{2}  \times 5 \times 12 \\ Area =  \frac{1}{ \cancel2}  \times 5 \times  \cancel{12}^{ \:  \: 6}  \\ Area = 5 \times 6 \\ Area = 30 \: units^{2}

Now add both areas for your answer

Area{ \tiny{1}} = 12 {units}^{2}  \\ Area{ \tiny2} = 30 {units}^{2}  \\ Area{ \tiny{total}} = Area{ \tiny{1}} + Area{ \tiny{2}} \\ Area{ \tiny{total}} = 12 + 30 = 42 {units}^{2}

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3 years ago
Find the slope of P = 59.7t + 21004.5
Furkat [3]

Step-by-step explanation:

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7 0
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Self explanatory solve porfavor
inessss [21]

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