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aleksandrvk [35]
3 years ago
15

What is the rectangular equivalence to the parametric equations?

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

Notice that

(<em>x</em> - 1)²/4 + (<em>y</em> + 2)²/9 = (2 sin(<em>θ</em>))²/4 + (3 cos(<em>θ</em>))²/9

… = sin²(<em>θ</em>) + cos²(<em>θ</em>)

… = 1

Solve for <em>y</em> in terms of <em>x</em> :

(<em>x</em> - 1)²/4 + (<em>y</em> + 2)²/9 = 1

(<em>y</em> + 2)²/9 = 1 - (<em>x</em> - 1)²/4

(<em>y</em> + 2)² = 9 - 9/4 (<em>x</em> - 1)²

<em>y</em> + 2 = ± √(9 - 9/4 (<em>x</em> - 1)²)

<em>y</em> + 2 = ± 3/2 √(4 - (<em>x</em> - 1)²)

<em>y</em> = -2 ± 3/2 √(4 - (<em>x</em> - 1)²)

In order for the square root to be defined, one needs

4 - (<em>x</em> - 1)² ≥ 0

(<em>x</em> - 1)² ≤ 4

-2 ≤ <em>x</em> - 1 ≤ 2

-1 ≤ <em>x</em> ≤ 3

so <em>x</em> must belong to the interval [-1, 3].

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