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3 years ago

Check whether the points ( -2, 3) , (8,3) ,(6,7) are the vertices of a right triangle

Mathematics

1 answer:

lora16 [44]3 years ago

8 0

Answer:

Given coordinetes of triangle A(−2,3),B(8,3) and C(6,7)

AB=

[8−(−2)]

+(3−3)

(10)

+(0)

100

AC=

[6−(−2)]

+(7−3)

(8)

+(4)

64+16

BC=

(6−8)+[7−(2)]

(−2)

+(4)

4+16

If ABC is a right angled triangle, then square of one side must be equal to sum of suare of other two sides.

100

)

=100

and AC

+BC

)

=100

∴AB

=AC

+BC

thus triangle satisfies the Pythagoras theorem

Hence, the triangle is right angled triangle.

Step-by-step explanation:

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Write an equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the l

mamaluj [8]

The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is $y = \frac{3}{4}x - \frac{5}{4}$

Solution:

The slope intercept form is given as:

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5

Given line is perpendicular to − 4 x − 3 y = − 5

− 4 x − 3 y = − 5

-3y = 4x - 5

3y = -4x + 5

$y = \frac{-4x}{3} + \frac{5}{3}$

On comparing the above equation with eqn 1, we get,

$m = \frac{-4}{3}$

We know that product of slope of a line and slope of line perpendicular to it is -1

$\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}$

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope $m = \frac{3}{4}$

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

$-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}$

$\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}$

$y = \frac{3}{4} \times x + \frac{-5}{4}\\\\y = \frac{3}{4}x - \frac{5}{4}$

Thus the required equation of line is found

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3 years ago