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xxTIMURxx [149]
3 years ago
9

Check whether the points ( -2, 3) , (8,3) ,(6,7) are the vertices of a right triangle

Mathematics
1 answer:
lora16 [44]3 years ago
8 0

Answer:

Given coordinetes of triangle A(−2,3),B(8,3) and C(6,7)

AB=  

[8−(−2)]  

2

+(3−3)  

2

 

​

=  

(10)  

2

+(0)  

2

 

​

=  

100

​

 

AC=  

[6−(−2)]  

2

+(7−3)  

2

 

​

=  

(8)  

2

+(4)  

2

 

​

=  

64+16

​

=  

80

​

 

BC=  

(6−8)+[7−(2)]

​

 

2

=  

(−2)  

2

+(4)  

2

 

​

=  

4+16

​

=  

20

​

 

If ABC is a right angled triangle, then square of one side must be equal to sum of suare of other two sides.

AB  

2

=(  

100

​

)  

2

=100

and AC  

2

+BC  

2

=(  

80

​

)  

2

+(  

20

​

)  

2

=100

∴AB  

2

=AC  

2

+BC  

2

 

thus triangle satisfies the Pythagoras theorem

Hence, the triangle is right angled triangle.

Step-by-step explanation:

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How many triangles can be constructed with angles measuring 80 degrees , 80 degrees and 40 degrees
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Answer:

None

Step-by-step explanation:

The angles inside a triangle add to 180. If the angles are 80, 80 and 40, then they must add to 180 to form a triangle.

80+80+40 = 200

This can't be a triangle.


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Please help!!!
Nonamiya [84]

Answer:

c. 2a^3x^4-3a^3x^3+a^4x^2

d. 63x^5y^3-30x^2y^4-7x^3y^2

Step-by-step explanation:

For this exercise you need to remember the following:

 1. The multiplication of signs:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-

2. The Product of powers property, which states that:

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3. The Distributive property:

a(b\±c)=ab\±ac

Knowing that, you can solve the multiplication of the polynomials:

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d. (6.3x^3y-3y^2-0.7x)(10x^2y^2)=\\\\=(6.3x^3y)(10x^2y^2)+(-3y^2)(10x^2y^2)+(-0.7x)(10x^2y^2)=63x^5y^3-30x^2y^4-7x^3y^2

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3 years ago
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