For this case we have the following function:
For each of the domains we will choose a value.
We have then:
For −5 ≤ x ≤ −1
Let's choose the value of x = -3
Evaluating the function we have:
Answer:
g(-3) = 1
For −1 < x ≤ 5:
Let's choose the value of x = 0
Evaluating the function we have:
Answer:
g(0) = 2
Answer:
The maximum height of the marshmallow is 49 feet.
Step-by-step explanation:
The vertex form of a parabola is
.... (1)
Where, (h,k) is vertex of the parabola is a is constant.
The given function is
..... (2)
Where, h is height of the marshmallow (in feet) and t is the time (in seconds) after he throws the marshmallow.
From equation (1) and (2), we get
The value of a is -16, which is less than 0. So, the given function is a downward parabola.
The vertex of a downward parabola is the point of maxima.
The value of h is 14 and the value of k is 49. So, the vertex of the parabola is (14,49). It means the maximum height of the marshmallow is 49 feet in 14 seconds.
Therefore the maximum height of the marshmallow is 49 feet.
Answer:
H was (Hx,Hy) goes to (Hy,-Hx)
G was (Gx,Gy) goes to (Gy,-Gx)
I was (Ix,Iy) goes to (Iy,-Ix)
Step-by-step explanation:
Rotating about the (0,0), the distance from any point to the origin (the hypotenuse of the triangle formed) never changes. A 90 clockwise rotation moves the point to the next quadrant, so side a and side b must flip to maintain the distance. You just need to flip the coordinates and change the sign of the new Y. If you plot a few random points and use a compass to rotate them 90 I think you will find this works.
Step-by-step explanation:
answer: counterclockwise rotation about the origin by 90degrees followed by reflection about the x-axis.
please give me brainliest:)
12(x^2+7)2−8(x^2+7)(2x−1)−15(2x−1)^2
Distribute:
=12x^4+168x^2+588+−16x^3+8x^2+−112x+56+−60x^2+60x+−15
Combine Like Terms:
=12x^4+168x^2+588+−16x^3+8x^2+−112x+56+−60x^2+60x+−15
=(12x^4)+(−16x^3)+(168x^2+8x^2+−60x^2)+(−112x+60x)+(588+56+−15)
=12x^4+−16x^3+116x^2+−52x+629
