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Ahat [919]
3 years ago
14

Owen has 12 pieces of rope that are 4 yards each. Owen uses 6 pieces of rope that are each 6 feet long.

Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0
Then, Owen only uses one piece of the 4 yard ropes.
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A summary measure that is computed to describe a population characteristic from a sample is called a: A) statistic. B) census. C
Juliette [100K]

Answer:

A. Statistic

Step-by-step explanation:

Usually whole population is difficult to cover so the part of population is considered to assess the aspects of population. The statistic is the quantity which summarizes the sample. The problem illustrate that summary measure is calculated from sample to describe a population. As the summary measure is computed from sample then it is a statistic.

5 0
3 years ago
Han ran 10 meters in 2.7 seconds.Priya ran 10 meters in 2.4 seconds.Who is faster?
ololo11 [35]

Answer:

Praiya lol

Step-by-step explanation:

Han ran 10 meters in 2.7 secs. Priya ran 10 in 2.4 secs. Do the math

4 0
3 years ago
Read 2 more answers
On Monday there are 25 pencils in a basket, If 3 pencils are taken out of the basket each day, how many pencils are left in the
lutik1710 [3]

13 cuz add 4 days then friday so 4×3 which is 12 and 12-25 so ye its 13

4 0
2 years ago
The end points of one diagonal of a rhombus are (-5,2) and (1,6). If the coordinates of the 3rd vertexare (-6,10), what are the
ad-work [718]
Look at the picture.

E\left(\dfrac{-5+1}{2};\ \dfrac{2+6}{2}\right)\to E\left(\dfrac{-4}{2};\ \dfrac{8}{2}\right)\to E(-2;\ 4)

\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]

D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}

8 0
3 years ago
Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the
mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

f(x)=Le^{-Lx}

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

f(x)=e^{-x}

For a)

P(T>2)

P(T>2)=1-P(T\leq 2)

P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx

P(T>2)=1-(-e^{-2}+1)

P(T>2)=e^{-2}=0.1353

For b)

P(T\geq 10/T>9)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

P(T\geq 10/T>9)=P(T\geq 1)

P(T\geq 1)=1-P(T

P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679

4 0
3 years ago
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