Answer:
Neither
Step-by-step explanation:
Check if it's arithmetic:
-8, -3, 6, 11, -22
+5 +6 +5 -33
Nope
Check if geometric:
-8, -3, 6, 11, -22
*3/8 *-2 *11/6 *-2
Nope
So it's neither
Complete question :
According to the National Beer Wholesalers Association, U.S. consumers 21 years and older consumed 26.9 gallons of beer and cider per person during 2017. A distributor in Milwaukee believes that beer and cider consumption are higher in that city. A sample of consumers 21 years and older in Milwaukee will be taken, and the sample mean 2017 beer and cider consumption will be used to test the following null and alternative hypotheses:
H, :μ< 26.9
Ha : μ> 26.9
a. Assume the sample data led to rejection of the null hypothesis. What would be your conclusion about consumption of beer and cider in Milwaukee?
b. What is the Type I error in this situation? What are the consequences of making this error?
c. What is the Type II error in this situation? What are the consequences of making this error?
Answer:
Kindly check explanation
Step-by-step explanation:
Given the null and alternative hypothesis :
H0 :μ< 26.9
Ha : μ> 26.9
Assume the Null hypothesis is rejected ;
We conclude that there is significant evidence that the mean consumption of beer and cider is higher in the city (more than 26.9 gallons).
B.) Type 1 error is committed when the Null hypothesis is incorrectly rejected.
C.) Type 2 error is committed when we fail to reject a false null hypothesis. In this scenario, we fail to conclude that the average consumption of beer and cider is more than 26.9 gallons per person.
-2 times 5 is -10 and then you add a 6 which equals -4
The probability of finding a substandard weld is: p = 5% =
0.05 <span>
We are given that the sample size: n = 300
Using the Poisson Distribution , the average number of welds (m) is:</span>
m = n*p =
m = 300 * 0.05 <span>
m =15 </span>
<span>
The standard deviation of welds (s) is calculated by:</span>
s = sqrt (m)
s = sqrt (15)
s = 3.873
<span>
<span>Assuming normal distribution, the z value corresponding to 30
sub standards is:
z =( X - Mean) / standard deviation
z =(30 - 15) / 3.873
z = 15 / 3.873
z = 3.87</span></span>
<span>
<span>The z value based on the standard normal curves has a maximum
value of 3.49. Beyond that z value of 3.49 would mean exceeding 100%. Therefore
z = 3.87 is not normal and definitely it is unusual to find 30 or more
substandard.</span></span>
