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2 years ago

Given the function f(x) = -5x + 11 + 3, for what values of x is f(x) = -12? Bleaseeeeee

Mathematics

2 answers:

Nitella [24]2 years ago

6 0

Answer:

x = 5.2

Step-by-step explanation:

$f(x) = -5x + 11 + 3$

Let's first simplify our first function:

$f(x) = -5x + 11 + 3\\f(x) = -5x + 14$

Now, we just need to set this function equal to our other given function.

$f(x) = -5x+14\\f(x) = -12\\-5x + 14 = -12$

Now, we can add 12 to both sides:

$-5x + 14 + 12 = -12 + 12\\-5x + 26 = 0$

Now, add 5x to both sides:

$-5x+26 = 0\\26 = 5x\\$

Finally, we'll divide both sides by 5:

$26/5 = 5x / 5\\5.2 = x\\x = 5.2$

Answer: x = 5.2

zhuklara [117]2 years ago

3 0

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2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$