Let a and b be irrational numbers. Is (ab)^2 always rational, sometimes rational, or never rational?

1 answer:

7 0

When you multiply 2 irrational numbers, the result is always irrational. This applies to squaring as well since it is still multiplying irrational numbers together (though the terms are the same)

Final answer: never rational

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The dimensions of a right rectangular prism are shown below. 1 in. 1a in. 2 in. in. How many cubes with side lengths of inch are

Dafna1 [17]

First we neeed to find the volume of the rectangular prism

$V=\text{ l}\times w\times h$ $V=1\times1\frac{1}{6}\times2\frac{1}{6}$ $=1\times\frac{7}{6}\times\frac{13}{6}$ $=\frac{91}{36}in^3$

Volume of cube with side lengths 1/6 = 1/6 x 1/6 x 1/6 = 1/216

The number of cubes needed to fill the prism without gaps or overlaps =

$=\frac{91}{36}\text{ divide by }\frac{1}{216}$ $=\frac{91}{36}\times\frac{216}{1}$ $=\frac{19656}{36}$ $=546$

3 0

1 year ago

If c(x) = 4x − 2 and d(x) = x² + 5x, what is (c.d)(x)?

snow_lady [41]

Answer:

$4x^2+20x-2$

Step-by-step explanation:

To find (c.g)(x) we basically use the function d(x) as your variable, x, and plug it into c(x). So we replace every x in c(x) with the function d(x), $x^{2} +5x$