Let a and b be irrational numbers. Is (ab)^2 always rational, sometimes rational, or never rational?
1 answer:
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Answer:
(-3/2, 6)
Step-by-step explanation:
(-3,8) (6,-4)
As we move along the line segment with endpoints (-3,8) and (6,-4) from (-3,8) to (6,-4) x increases by 9 units (from -3 to 6) and y decreases by -12 units (from 8 to -4).
for ratio of 1:5
Since 1+5=6, the point we are looking for is 1/6 of the way from (-3,8) to (6,-4).
So, the desired point is
(-3 + (1/6)(9), 8 - (1/6)(12) )
= (-3 + 3/2 , 8 - 2)
= ( (-6 + 3)/2, 6)
= (-3/2, 6)
for map reference see the image below
