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Inessa05 [86]
3 years ago
10

Write the polynomial in standard form -7x+10x^3-7x^2-x^8+15

Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

-x^8+10x^3-7x^2+7x+15

Step-by-step explanation:

-7x+10x^3-7x^2-x^8+15

Standard form is from highest power to lowest power of x

-x^8+10x^3-7x^2+7x+15

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Solve -2x + 6 = -20. -13 13 -7 7
alexdok [17]

Note the equal sign. What you do to one side, you do to the other.

Also, remember to do the opposite of PEMDAS.

First, subtract 6 from both sides

-2x + 6 (-6) = -20 (-6)

-2x = -26

Next, isolate the x. Divide -2 from both sides

(-2x)/-2 = (-26)/-2

x = -26/-2

x = 13

13, or (B) is your answer

---------------------------------------------------------------------------------------------------------------------  

<em>~Rise Above the Ordinary, Senpai</em>

8 0
3 years ago
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Which of the following terminating decimals is equivalent to Negative 1 and three-fourths?
Tems11 [23]

Answer:

-1.75

Step-by-step explanation:

This should be it, but you didn't provide options although you put "Which of the following.."

3 0
2 years ago
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This question has three parts. Answer the parts in order.
nalin [4]

Answer:

The area of the smallest section is A_{1}=100yd^{2}

The area of the largest section is A_{2}=625yd^{2}

The area of the remaining section is A_{3}=250yd^{2}

Step-by-step explanation:

Please see the picture below.

1. First we are going to name the side of the larger square as x.

As the third section shares a side with the larger square and the four sides of a square are equal, we have the following:

- Area of the first section:

A_{1}=10yd*10yd

A_{1}=100yd^{2}

- Area of the second section:

A_{2}=x^{2} (Eq.1)

- Area of the third section:

A_{3}=width*length

A_{3}=10yd*x (Eq.2)

2. The problem says that the total area of the enclosed field is 975 square yards, and looking at the picture below, we have:

A_{1}+A_{2}+A_{3}=975yd^{2}

Replacing values:

100+x^{2}+10x=975

Solving for x:

x^{2}+10x-875=0

x=\frac{-10+\sqrt{100+(4*875)}}{2}

x=\frac{-10+\sqrt{3600}}{2}

x=\frac{-10+60}{2}

x=25

3. Replacing the value of x in Eq.1 and Eq.2:

- From Eq.1:

A_{2}=25^{2}

A_{2}=625yd^{2}

- From Eq.2:

A_{3}=10*25

A_{3}=250yd^{2}

3 0
3 years ago
What ratio is proportional to 18/21
Doss [256]

Answer:

There are many.

Step-by-step explanation:

When you say proportional, you are looking for a ratio that is equivalent to the ratio given. In your case, there are many so you might need to be more specific. But still, we can help you figure it out.

An easy way to do this would be to scale it down to its simplest form and then move upwards. To find proportional ratios, just multiply denominator and the denominator with the same factor.

\dfrac{18}{21} = \dfrac{6}{7}

That is your ratio in its simplest form. Now we can scale up, I'll show you how to do one completely:

\dfrac{6}{7} x \dfrac{2}{2} = \dfrac{12}{14}

That's the same ratio scaled up by a factor of 2.

---------------------------------------------------------------------------------------

\dfrac{6}{7} x \dfrac{3}{3} = \dfrac{18}{21}

That's the ratio given

---------------------------------------------------------------------------------------

\dfrac{6}{7} x \dfrac{4}{4} = \dfrac{24}{28}

Scaled up by a factor of 4

---------------------------------------------------------------------------------------

\dfrac{6}{7} x \dfrac{5}{5} = \dfrac{30}{35}

Scaled up by a factor of 5.

The list goes on and on.


3 0
3 years ago
Please find the missing side of this triangle
umka21 [38]

Answer:

The answer is 8.30

Step-by-step explanation:

Using cos 41 = x/11

x = cos 41 × 11

x = 8.30

4 0
3 years ago
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