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kherson [118]
3 years ago
10

Divide. 42/−8 Enter your answer as a mixed number, in simplified form, in the box.

Mathematics
2 answers:
maks197457 [2]3 years ago
6 0

Answer:

The answer is -5 1/4!

Hope this helped! :)



^-^


Stells [14]3 years ago
4 0
To solve, you have to first find out how many times -8 goes into 42. That would be 5 times, so your mixed number would first be 5. The remainder from 5*8=40 would be 2 because 42-40=2 so the fraction part would be 2/8 or 1/4 if you simplify so when u add the negative, your answer will be -5 1/4.
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The second floor of a house consists of a master bedroom, kid's bedroom, and bathroom.
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What is the factorization of 2x²+7x+6
Kipish [7]

[ Answer ]

\boxed{\bold{(2x \ + \ 3)(x \ + \ 2)}}

[ Explanation ]

  • Factor: \boxed{\bold{2x^{2} \ + \ 7x \ + \ 6} }}

----------------------------------

  • Break The Expression Into Groups

(2x^{2} + 3x) + (4x + 6)

  • Factor Out X From 2x^{2} + 3x: x(2x + 3)

  • Factor Out 2 From 4x + 6: 2(2x + 3)

x(2x + 3) + 2(2x + 3)

  • Factor Out Common Term 2x + 3

(2x + 3)(x + 2)

\boxed{\bold{[] \ Eclipsed \ []}}

5 0
3 years ago
Find the midpoint of the line segment with the given endpoints.<br> (-10,-4), (6,-5)
zaharov [31]
Midpoint: ((x1+x2)/2, (y1+y2)/2)
-10+6 = -4/2 = -2
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8 0
3 years ago
A small town has 3500 families. The population mean (mu) number of children per family is = 3, with a population standard deviat
natita [175]

Answer:

Let X the random variable that represent the variable of interest of a population, and for this case we know the following info:

Where \mu=3 and \sigma=0.6

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the mean of this distribution is:

\mu_{\bar X}= \mu= 3

And the deviation is:

\sigma_{\bar X}= \frac{0.6}{\sqrt{100}}= 0.06

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the following info:

Where \mu=3 and \sigma=0.6

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the mean of this distribution is:

\mu_{\bar X}= \mu= 3

And the deviation is:

\sigma_{\bar X}= \frac{0.6}{\sqrt{100}}= 0.06

4 0
3 years ago
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