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mr Goodwill [35]
3 years ago
8

I need help with my homework pls somone help….

Mathematics
2 answers:
Vikki [24]3 years ago
5 0

Answer:

x > 9

Step-by-step explanation:

since the dot is open there won't be a line under

kvv77 [185]3 years ago
5 0

Answer:

X > 9

Step-by-step explanation:

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I need help pls and ty
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Answer: 3rd option

Step-by-step explanation: square root of 13 is 3.60 so it lines up perfectly on the number line

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What is the slope of a line that passes through 4,-3 and -8,4
trapecia [35]

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Step-by-step explanation:

Hope this helps : )

7 0
4 years ago
Read 2 more answers
Let <img src="https://tex.z-dn.net/?f=%5Calpha" id="TexFormula1" title="\alpha" alt="\alpha" align="absmiddle" class="latex-form
Margarita [4]

Answer:

|\alpha| = 2

Step-by-step explanation:

Since \alpha and \beta are complex conjugates, let's define them as follows:

\alpha = a+bi

\beta = a-bi

\frac{\alpha}{\beta^2}=\frac{a+bi}{a^2-b^2-2abi} =\frac{(a+bi)*(a^2-b^2+2abi)}{(a^2-b^2-2abi)*(a^2-b^2+2abi)} =\frac{a^3-3ab^2+(3a^2b-b^3)i}{a^4+2a^2b^2+b^4}

Since \frac{\alpha}{\beta^2} is a real number, complex part of above result must be zero.

3a^2b-b^3=0

From to hold above equality, b=0 or b^2=3a^2.

However, since |\alpha-\beta|=2\sqrt 3, b\neq 0

So, b =\sqrt 3 a or b =-\sqrt 3 a

And since \alpha and \beta are complex conjugates, taking plus or minus sign as found above will not affect the result, so let's write the last version of \alpha and \beta as follows:

\alpha = a+\sqrt 3 ai

\beta = a-\sqrt 3 ai

Since |\alpha-\beta|=2\sqrt 3

|a+\sqrt 3 ai-a+\sqrt 3 ai|=2\sqrt 3 ⇒ a = 1

Finally, \alpha = 1+\sqrt 3 i ⇒ |\alpha| = \sqrt{(1^2+\sqrt 3^2)}=2

3 0
3 years ago
Omar bought one dozen eggs for 2.69. which is the amount Omar paid for each egg​
4vir4ik [10]

Answer:

about 23 cents per egg

Step-by-step explanation:

5 0
3 years ago
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