Answer:
i think its twelve nine and five
Step-by-step explanation:
not one hundred percent sure
Answer:
(a) 218.6 N
(b) 97.14 N
Step-by-step explanation:
When the system is in equilibrium, the net torque on the system is zero.
AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m
Let the centre of gravity of plank is at G.
AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m
(a) Let the reaction at C is R and at D is R'.
R + R' = 29 x 9.8 = 284.2 N ... (1)
Take the torque about C.
29 x 9.8 x CG = R' x GD
29 x 9.8 x 1 = R' x 1.3
R' = 218.6 N
(b) Take the torque about D.
6 x 9.8 x AD = R x CD
6 x 9.8 x (1.5 + 2.3) = R x 2.3
R = 97.14 N
Answer:
21 students pass
Step-by-step explanation:
Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction 
(which is 75% represented as a fraction).
The fraction can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with 
.
Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.
The denominators cancel out leaving you with a simple equation to simplify.
Finally, divide both sides by four in order to isolate the variable.
X = 21.
Answer:
Area of A = 32ft
Area of B = 36ft
Step-by-step explanation:
All you need to do to solve is multiply width * length * height.
If you do so,
Area of A = 3 * 2 * 5 1/3
= 6 * 16/3
= 32
Area of B = 6 * 4 * 1 1/2
= 24 * 3/2
= 36
Hope this helps!!
Let me know if I'm wrong or you need help in any other problem!!
