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2 years ago

15

Evalute 8-2 .3 +7 ............................................................................................................

1 answer:

Orlov [11]2 years ago

6 0

Answer:

vehrjebdhrhejegdduehegdudhsgdhdhsvxuaj

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What is the point of intersection when the system of equations below is graphed on the coordinate plane?

lesantik [10]

Multiply the first equation by -2 gives:_
-2y = -8 + 2x

2y = 8 - 2x

adding these 2 equations:-

0 = 0

This shows that the 2 equations are equal so there are infinite solutions

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2 years ago

2/3 - 1/5 as a fraction

Goryan [66]

Answer:

Step-by-step explanation:

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3 years ago

Solve the following equation for x: 6(4x+5)= 3(x+8)+3. Round to the nearest hundredth.

gavmur [86]

6(4x + 5) = 3(x + 8) + 3
24x + 30 = 3x + 24 + 3
24x + 30 = 3x + 27
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2 years ago

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If sea level = 0, write an integer that represents 25 feet below sea level.

Svetach [21]

Answer: -25

Step-by-step explanation:

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2 years ago

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BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

8 0

2 years ago