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Aleks04 [339]
3 years ago
15

A multiple - choice test consists of 10 questions each question has a answer choice of a b c d and only one of them is correct i

f a student guess on each question what the probability the she gets more than 2 of them correct
Mathematics
1 answer:
jenyasd209 [6]3 years ago
8 0

Use Ga_thMath(u) (brainly doesn't allow me to type it) To use the app u need to take a pic of the problem and then it will process it and you'll get ur answer ASAP(most of the time). Many questions have been asked before so search it on brainly.

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A pizza place offers 3 different cheeses and 12 different toppings. In how many ways can a pizza be made with 1 cheese and 3 top
svetlana [45]
You have to choose 1 sort of cheese from 3 ( 3 ways ). Also you have to choose 3 toppings from 12 different toppings:
12 * 11 * 10 = 1,320 ways.
In total: 3 * 1,320 = 3,960
Answer:
In 3,690 ways can pizza be made with 1 cheese and 3 toppings.
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4 years ago
How would you find the zero of f (x)=16x^4 - 9x^2
krok68 [10]
f (x) = 16x ^ 4 - 9x ^ 2 \\ \\16x ^ 4 - 9x ^ 2=0\\ \\x^2(16x^2-9)=0 \\ \\x^2 =0 \ \ or \ \ 16x^2-9=0\\ \\ x=0 \ \ or \ \ (4x-3)(4x+3)=0\\ \\ x=0 \ \ or \ \  4x-3=0 \ \ or \ \ 4x+3 =0\\ \\x=0 \ \ or \ \  4x=3 \ \ / :4 \ \ or \ \ 4x=-3\ \ / :4 \\ \\ x=0 \ \ or \ \   x=\frac{3}{4} \ \ or \ \  x=-\frac{3}{4}
3 0
3 years ago
Read 2 more answers
HELP PLEASE<br><br> ((ATTACHMENT TO HELP ANSWER, BECAUSE THERE'S REALLY NO QUESTION WITH IT))
BabaBlast [244]
Linear- blue graph, table 2, 2x-3y=7, y=3\x +2, y=-4
Nonlinear- y= 2x^2+ 4
7 0
4 years ago
Wrong question was asked
tiny-mole [99]

Step-by-step explanation:

what's the question, please can you kindly resend it, thanks

3 0
3 years ago
Read 2 more answers
Refer to the random sample of customer order totals with an average of $78.25 and a population standard deviation of $22.50. a.
zysi [14]

Answer:

a) 78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416

78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084

b) 78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989

78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

d)   ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

Solving for n we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

And replacing the info we have:

n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55

Step-by-step explanation:

Part a

For this case we have the following data given

\bar X = 78.25 represent the sample mean for the customer order totals

\sigma =22.50 represent the population deviation

n= 40 represent the sample size selected

The confidence level is 90% or 0.90 and the significance level would be \alpha=0.1 and \alpha/2 = 0.05 and the critical value from the normal standard distirbution would be given by:

z_{\alpha/2}=1.64

And the confidence interval is given by:

\bar X -z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

And replacing we got:

78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416

78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989

78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

 ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

Solving for n we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

And replacing the info we have:

n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55

3 0
3 years ago
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