Answer:
Center: (6, -12)
Radius: 4
Step-by-step explanation:
<u>Complete the squares</u>
<u />
Comparing with the standard form equation
, since
, then the radius of the circle is
. Also, the center of the circle would be
.
When two polynomials are multiplied, each term of the first polynomial is multiplied by each term of the second polynomial. ... The result is always a polynomial, regardless what the coefficients might be of any of the terms, including the leading coefficients.
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Calculus</u>
Discontinuities
- Removable (Holes)
- Jump (Piece-wise functions)
- Infinite (Asymptotes)
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Simplify</u>
- [Frac - Numerator] Factor quadratic:

- [Frac - Denominator] Factor GCF:

- [Frac] Divide/Simplify:

When we divide (x + 2), we would have a <em>removable</em> <em>discontinuity</em>. If we were to graph the original function, we would see at x = -2 there would be a hole in the graph.
Given that,
Length of a rectangular courtyard = (3x+5)
Width of a rectangular courtyard = (2x-3)
To find,
The expression for area of the courtyard.
Solution,
The area of the rectangular shaped object is given by :
A = lb
Substituting all the values,
A = (3x+5) (2-3)
= (3x)(2)-(3x)(3)+(5)(2)-(5)(3)
= 6x-9x+10-15
= -3x-5
So, the area of the courtyard is (-3x-5).
M+2/3=1/2
<=> m= 1/2 - 2/3
<=> m= -1/6