Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
Answer:
There are two solutions to this problem.
x=4
or
x=-4
Step-by-step explanation:
Answer:
12) A ( 9, 11, 13, 15)
13) A ( o , a)
14) A (b ∈ ( a, b, c, d, e, f))
15) C ( -364)
16) D (-1°C)
17) B (Negative)
18) C (26 feet)
19) B (7)
Step-by-step explanation:
12) All of these are odd numbers greater than 7
13) These are the only vowels in "MONDAY"
14) Point B cannot belong in a set that already has B
15) -9876 + 9512 = -364
16) 4 - 5 = -1
17) ex: -2 + (-2) = -4
18) -20 + 12 - 18 = -26
19) 3(5) + 4(-2) = 15 - 8 = 7
-Chetan K
Answer:
Common difference is 4
Step-by-step explanation:
25 , 29, 33,37,41
Answer:
Step-by-step explanation:
21(5m - 3) = 63*9
105m - 63 = 567
105m = 630
m = 6
