All categories

3 years ago

19 - k = 4. I need help

Mathematics

1 answer:

Marysya12 [62]3 years ago

5 0

Answer:

Step-by-step explanation:

first you have to subtract 4 from 19 to get what k is. that should be your answer. good luck!

You might be interested in

In trapezoid ABCD with legs AB and CD , diagonals BD ∩ AC =M so that BM:MD=1:4. Find AAMD, ACMD, and AACD if the area of AABM=8

bazaltina [42]

Answer:

Area of triangle AMD is 32 square inches.

Area of triangle CMD is 8 square inches.

Area of triangle ACD is 40 square inches.

Step-by-step explanation:

In trapezoid ABCD with legs AB and CD.

Diagonal BD and AC intersect at M so that BM:MD=1:4

We are given ar(ABM)=8 in²

Ratio of area of two triangle is equal to ratio of their base.

$\dfrac{ar(ABM)}{ar(AMD)}=\dfrac{BM}{MD}$

$\dfrac{8}{ar(AMD)}=\dfrac{1}{4}$

$ar(AMD)=32\text{ in}^2$

Thus, Area of triangle AMD is 32 square inches.

If two triangles lie on same base and same parallel line then their area is equal.

$\therefore ar(ABD)=ar(ACD)$

$ar(ACD)=ar(ACD)=ar(AMD)+ar(ABM)$

$ar(ACD)=8+32\Rightarrow 40\text{ in}^2$

Thus, Area of triangle ACD is 40 square inches.

$ar(CMD)=ar(ACD)-ar(AMD)$

$ar(CMD)=40-32\Rightarrow 8\text{ in}^2$

Thus, Area of triangle CMD is 8 square inches.

5 0

4 years ago

I will give brainiest to whoever answers correctly !!

WINSTONCH [101]

Answer:

Step-by-step explanation:

I don’t know the answer I just need some points to ask more questions

5 0

3 years ago

Which statements must be true regarding the two triangles? Check all that apply. M M" O LMN - L"M"N" O LMN 2 L"M"N"

blagie [28]

Answer: The 1st, 2nd, and 5th one

Step-by-step explanation:

just did it

8 0

3 years ago

Read 2 more answers

Police plan to enforce speed limits by using radar traps at four different locations within the city limits. The radar traps at

dalvyx [7]

Answer:

The probability that the person gets a speeding ticket is 0.27

Step-by-step explanation:

The probability that the person receives a speeding ticket is the probability that the person passes through any of the speed limits and the radar is operating at that time.

Let $P(L_1)$ is the probability that the person passes through radar $L_{1}$ and it is operating at that time is

$P(L_{1})=P(1)\times P(2)$

Where

P(1) is the probability of person passes through $L_{1}$

P(2) is probability that the radar is operating

$P(L_1)=0.2\times 0.4=0.08$

Similarly the probabilities are calculated for other radars in the similar manner as

$P(L_2)=0.1\times 0.3=0.03$

$P(L_3)=0.5\times 0.2=0.1$

$P(L_4)=0.2\times 0.3=0.06$

Thus the reuired probability of the reuired event is

$P(E)=P(L_1)+P(L_2)+P(L_3)+P(L_4)\\\\P(E)=0.08+0.03+0.1+0.06=0.27$

8 0

3 years ago

Some paint is made by mixing 2 cans of white paint for every 5 cans of red

Allushta [10]

5.2

Explanation in the photo

8 0

2 years ago

19 - k = 4. I need help​

19 - k = 4. I need help