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pav-90 [236]
4 years ago
14

Evaluate the expression for the given values.

Mathematics
1 answer:
blagie [28]4 years ago
3 0

we have given an expression mx-y.

we have given the value of x,y and m .

m=5,x=3,y=8.

we need to find the value of expression mx-y.

we need to plug the respective values and solve.

mx-y=(5)*(3)-(8)=15-8=7..

7 is the value of expression mx-y.

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Use the identity below to complete the tasks:
Gennadij [26K]

Answer:

a3+b3=(a+b)(a2-ab+b2)

4 0
3 years ago
Can someone please help me? I can't find the h(x) for 0. I also need help with the last question. Please I need it very soon.
Solnce55 [7]

9514 1404 393

Answer:

  see attachments for a table and graph

Step-by-step explanation:

I find it convenient to use a graphing calculator or spreadsheet to do repetitive computations reliably.

__

Your specific question asks for h(0):

  h(0) = -|0 +2| +1 = -2 +1

  h(0) = -1

You may want to check your other table values.

8 0
3 years ago
What is the solution to the expression -2-3-(-4)?
alexgriva [62]
Answer: -1

-2-3-(-4)
-5-(-4)
-1
5 0
3 years ago
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Can anyone help me I was self isolating when my class was taught this and I can't get in contact with my teacher
Aleonysh [2.5K]

Answer:

Step-by-step explanation:

3x +2y = 13   -----------------(i)

x + 2y = 7    ----------------(ii)

Multiply the equation (ii) by (-1) and then add.

(i)              3x + 2y = 13

(ii)*(-1)      <u>-x    - 2y = -7 </u>        {Now, add and y will be eliminated}

                 2x       = 6

                        x = 6/2

x = 3

Plug in x = 3 in equation (i)

3*3 + 2y = 13

  9 + 2y = 13

         2y= 13 - 9

         2y = 4

           y = 4/2

y = 2

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Arrange the steps to solve the equation square root x+3 - square root 2x-1=-2
stiv31 [10]

Answer:x=31.4919

Step-by-step explanation:

Step1:isolate a square root on the left hand side√x+3=√2x-1-2

Step2:eliminate the radicals on the left hand side

Raise both sides to the second power

√x+3)^2=(√2x-1-2)^2

After squaring

x+3=2x-1+4-4-4√2x-1

Step3:get the remaining radicals by itself

x+3=2x-1+4-4√2x-1

Isolate radical on the left hand side

4√2x-1=-x-3+2x-1+4

4√2x-1=x

Step4:eliminate the radicals on the left hand side

Raise both side to the second power

(4√2x-1)^2=x^2

After squaring

32x-16=x^2

Step 5:solve the quadratic equation

x^2-32x-16

This equation has two real roots

x1=32+√960/2=31.4919

x2=32-√960/2=0.5081

Step6:check that the first solution is correct

Put in 31.4919 for x

√31.4919+3=√2•31.4919-1-2

√34.492=5.873

x=31.4919

Step7:check that the second solution is correct

√x+3=√2x-1-2

Put in 0.5081 for x

√0.5081+3=√2•0.5081-1-2

√3.508=-1.873

1.873#-1.873

One solution was found

x=31.4919

6 0
3 years ago
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