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2 years ago

I’m so confused what is answer to the value of x HELPPP

Mathematics

2 answers:

Vesna [10]2 years ago

7 0

Answer:

2.5 or 5/2

Step-by-step explanation:

Vertical angles are a pair of non-adjacent angles formed by the intersection of two straight lines. In simple words, vertical angles are located across from one another in the corners of the "X" formed by two straight lines. They are also called vertically opposite angles as they are situated opposite to each other - in other words, separated by the crossing point of the two lines, and not by the lines themselves.

that also means that they are equal.

and so,

8x + 15 = 4x + 25

4x = 10

x = 10/4 = 5/2 = 2.5

Maurinko [17]2 years ago

4 0

Answer:

x=5/2 or 2.5

Step-by-step explanation:

See the image for solution

Hope it helps

Have a great day

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Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

2 years ago

Use the substitution method to solve the following system of equations: 3x + 5y = 3 x + 2y = 0 (1 point) (1, 1) (6, −3) (6, 1) (

PtichkaEL [24]

Step-by-step explanation:

Given.

$3x+5y=3$

$x+2y=0$

Take the second equation and subtract 2y to both sides.

$(x+2y)-2y=0-2y$

$x=-2y$

Substitute x into the first equation and simplify.

$3x+5y=3$

$3(-2y)+5y=3$

$-6y+5y=3$

$-y=3$

Invert.

$y=-3$

Substitute Y into your second equation.

$x+2y=0$

$x+2(-3)=0$

$x-6=0$

Add -6 to both sides.

$(x-6)+6=0+6$

$x=6$

Answer:

(6, -3)

6 0

2 years ago

the population of center city is modeled by exponential function f, where x is the number of years after the year of 2015. the g

lora16 [44]

Answer:

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2 years ago

Determine the domain and range of the graph.

nirvana33 [79]

Answer:

Domain [-4,4]

Range [-2,2]

Step-by-step explanation:

The domain is the x-values of the graph and the range in the y-values. When writing domain and range it should be from least to greatest. So to find the domain find the lowest x-value on the graph and then the highest. Next, do the same for y-values. Finally, either surround each value with parentheses or bracket, the difference is that brackets mean that value is included, while parentheses mean that value is not actually on the graph.

In this case, the lowest x-value is -4 and the highest is 4, both values are included as signified by the closed circles, therefore the domain is [-4,4]. The lowest y value is -2 and the highest is 2, both are included, therefore the range is [-2,2].

4 0

2 years ago

A rocket is launched from ground level. The height of the rocket can be

abruzzese [7]

Answer: 11.25 secs

Step-by-step explanation:

So in this sense the rockets origin or the ground is modeled at h=0 so the time required if used on a table shows that h=0 between the values of 11 and 12. So if you plug and chug decimal values between these two values you get exactly 0 at t=11.25 so it takes approximately 11.25 seconds for the rocket to return to the ground

3 0

2 years ago