You basically would just divide, $24.18 by 3 . since they split the cost.
Answer:
P(X < 80) = 0.89435.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

P(X < 80)
This is the pvalue of Z when X = 80. So



has a pvalue of 0.89435.
So
P(X < 80) = 0.89435.
5 is the difference.
Note: Minuend - Subtrahend = Difference
Answer:
a0) 2
x<0
a1) x
0≤x<3
a2) 3
x≥3
Step-by-step explanation:
As shown in the given graph
function of y is a straight line at y=2 line till x=0
hence a0:
y= 2 for x<0
Then function becomes linear line from x=0 till x=3
hence a1:
y= x for 0≤x<3
Now after that graph of function y again shift to straight line from x=3 onward with y-axis value of 3
hence a2:
y= 3 for x≥3 !
Answer:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

92% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).