Answer:
P ( X > 5 ) = 72,2 %
Step-by-step explanation:
The probability of success ( outcomes bigger than 5 )
If dice 1 outcome is 6 no matter wich outcome we get from dice 2 all events are successful, the we have 6 outcomes
If dice 1 outcome is 5 we also have 6 outcomes
If dice 1 outcomes is 4 we have 5 positive outcomes
If dice 1 outcome is 3 we have 4 positive outcomes
If dice 1 outcome is 2 we have 3 positive outcomes
if dice 1 outcome is 1 we have 2 positive outcomes
Total evaluating dice 1: positive outcomes 26
We will get the sames results analysing dice 2 then we have a total of
52 successful events
And total numbers of outcomes is 36 + 36 = 72
Then
P ( X > 5 ) = 52/72
P ( X > 5 ) = 0,722
P ( X > 5 ) = 72,2 %
The answer is A, because 43 of the flights were from UA and were on time, this is out of a whole of 87 flights.
Answer:
the answer the B
Step-by-step explanation:
Answer:
4.121216129m
Step-by-step explanation:
use sohcahtoa
tan(70) x 1.5m = 4.121216129m
Answer: 3,19 which is larger than the original
Step-by-step explanation: if you consider that the original average is 3 you can say that all 25 students have 3 siblings so the average is 3, if you add another students with 8 siblings and do some math (25*3+8)/26 its 3,19