Answer:
Explanation:
Translate every verbal statement into an algebraic statement,
<u>1. Keith has $500 in a savings account at the beginning of the summer.</u>
<u>2. He wants to have at least $200 in the account by the end of summer. </u>
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<u>3. He withdraws $25 a week for his cell phone bill.</u>
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- Call w the number of weeks
<u>4. Write an inequality that represents Keith's situation.</u>
- Create your model: Final amount = Initial amount - withdrawals ≥ 500
With that inequality you can calculate how many week will pass before his account has less than the amount he wants to have in the account by the end of summer:
That represents that he can afford spending $ 25 a week during 12 weeks to have at least $ 200 in the account.
Answer: (4x+12) - (2x-5)
Step-by-step explanation: The (4x+12) is positive and the (2x-5) is negative.
PART A:
The given quadratic equation is 2x²-10x-8=0
The radicand is given by b²-4ac where a, b, and c are the constants in a quadratic form ax²+bx+c
From the given equation, we have
a = 2
b = -10
c = -8
Radicand b²-4ac = (-10)² - 4(2)(-8) = 100 + 64 = 164
The radicand is >0 hence the quadratic equation has two distinct roots
PART B:
4x²-12x+5 = 0
We can use the factorization method to solve the equation
Firstly, we multiply 4 by 5 to get 20
Then we find the pair of numbers that multiply gives 20 and sum gives -12
The pair of number is -2 and -10
Rewriting the equation
4x²-2x-10x+5 = 0
2x(2x-1)-5(2x-1) = 0
(2x-1)(2x-5) = 0
2x-1 = 0 and 2x-5 = 0
x = 1/2 and x = 5/2
(4x-3y)^2(4x-3y)
=(16x^2-24xy+9y^2)(4x-3y)
=64x^3-96x^2y+36xy^2-48x^2y+72xy^2-27y^3
=64x^2-144x^2y+108xy^2-27y^3
Answer:
y≤−6. Everthing more or equal to -6 should be shaded. So like fro-6 to -10
Step-by-step explanation:
Multiply each term in 12y≤−3 by 2 to eliminate the fractions.
