Let s be Seth's age. let r be Romans age. 5 years ago Seth was s-5 and Roman was three times as old, or 3(s-5), or 3s-15=r-5
in ten years Seth will be s+10 and Roman will be twice as old, or 2(s+10), or 2s+20=r+10
3s-15 =r-5
r=3s-10
2s+20=r+10
r=2s+10
3s-10=2s+10
s=20
Seth is 20 years old
setting the two equations equal gives us
3(s-5)=2(s+10)
3s-15=2s+20
s=35
Answer:
The third answer
Step-by-step explanation:
Remember power over root and the 2 would not be under the root.
What's the question? I'll help with it as much as I can :)
Answer:
The raw score for his exam grade is 99.69.
Step-by-step explanation:
Given : The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67.
To find : What is the raw score for his exam grade?
Solution :
The formula use to find the z-score is
Where, z=1.67 is the z-score
is the means
is the standard deviation
x is the raw score for his exam grade
Substitute the values,
Therefore, the raw score for his exam grade is 99.69.
<span>Susanne is 16 years old.</span>
b = Bob's age
s = Susanne's age
d = Dakota's age
Bob's age is 4 times greater than Susanne's age:
b = 4s
Dakota is three years younger than Susanne:
d = s - 3
The sum of Bob's, Susanne's, and Dakota's ages is 93:
b + s + d = 93
solve these equations:
b = 4s
d = s - 3
b + s + d = 93
and get:
b = 64 years
s = 16 years
(remember that s = Susanne)
d = 13 years
