Answer:
10:30PM on the next day
Step-by-step explanation:
First movie = 85mins
intermission = 5mins
Total time = 90mins which is 1:30PM
so the first movie will start again at 1:30PM, which is at the interval of 90minutes and it will run continuously.
Similarly the second movie is 110 minutes long + 5mins intermission which is 115minutes
Time = 1:55PM
so the second movie starts again at 1:55PM and runs continuously at an interval of 115minutes.
We are interested to find when both the movie will start again at the same time, this will be least common multiple of 90 and 115.
LCM of 90,115 = 2070
Therefore after 2070minutes movie will start again at the same time.
2070mins = 34hours and 30 minutes
adding this with noon
10:30PM on the next day.
Answer:
200n - 162.
Step-by-step explanation:
first trem a1 = 38
common difference d = 200
nth term = a1 + (n-1(d
= 38 + 200(n-1)
= 200n - 162
=
First, simplify
to
/ Your problem should look like:
=
Second, multiply both sides by 5. / Your problem should look like: 6 = 2n
Third, divide both sides by 2. / Your problem should look like:
= n
Fourth, simplify
to 3. / Your problem should look like: 3 = n
Fifth, switch sides. / Your problem should look like: n = 3
Answer:
n = 3
The answer to the question is a
