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trapecia [35]
3 years ago
10

Three measurements are made on each of three individuals in a random sample from a population. X 1 = 2, X2 = 8

Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Step-by-step explanation:

here is the answer hope it helps

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Two angles of a triangle have measures of 55° and 65°.
ivann1987 [24]
The third angle is 180-55-65 = 60°.

Exterior angles are 180-55 = 125°, 135°, 120°
7 0
3 years ago
Factorise a squared - b squared
marusya05 [52]
(a-b)(a+b) because when you reverse the sum you do axa and ax-b xx
5 0
4 years ago
it's asking to write an equation in slope-intercept form for the line with slope -4 and y-intercept 7. then graph the line. plea
LuckyWell [14K]

Answer:

Equation = y = -4x+7

See the graph below

Step-by-step explanation:

The equation of the line in slope intercept form is expressed as;

y = mx+c

Given

slope m = -4

y-intercept c = 7

Substitute

y = -4x + 7

Get the x intercept.

at y = 0

0 = -4x + 7

4x = 7

x = 7/4

x = 1.75

The x coordinate  (1.75, 0)

Get the y intercept

at x = 0;

y = -4(0)+7

y = 0+7

y = 7

The y coordinate is (0, 7)

5 0
3 years ago
Find the slope of the line that passes through the points (-12,10) and (-18,14).
9966 [12]

Answer:

-2/3

Step-by-step explanation:

To find the slope we use the formula

m= ( y2-y1)/(x2-x1)

   = ( 14-10)/(-18- -12)

   = (14-10)/(-18+12)

  = 4/-6

 = -2/3

5 0
3 years ago
Find the coordinates of the orthocenter of a triangle with the vertices (5,3), (8,6), (0,14) at each set of points on a coordina
Irina-Kira [14]

Answer:

coordinates of the orthocenter = (8, 6)

Step-by-step explanation:

I have drawn a diagram showing this triangle with the vertices. I have also drawn altitude from B perpendicular to AC at point E.

I have also drawn altitude from from A perpendicular to BC at point D.

Now, we will find the slope of AC from the line slope equation; (y - y1) = m(x - x1)

m = (y - y1)/(x - x1)

Our coordinates are; A(5,3), B(8,6), C(0,14)

Thus;

Slope of AC; m = (14 - 3)/(0 - 5)

m = -11/5

Since BE is perpendicular to AC, slope of BE = -1/slope of AC = -1/(-11/5) = 5/11

Thus, equation of BE is;

(y - 6) = (5/11)(x - 8)

Multiply through by 11 to get;

11y - 66 = 5x - 40

11y - 5x = 66 - 40

11y - 5x = 26

Slope of BC is; m = (14 - 6)/(0 - 8) = 8/-6 = -1

AD is perpendicular to BC, thus slope of AD = -1/-1 = 1

Equation of AD is;

(y - 3) = 1(x - 5)

y - 3 = x - 5

y = x - 5 + 3

y = x - 2

Putting x - 2 for y in equation of BE, we have;

11(x - 2) - 5x = 26

11x - 22 - 5x = 26

6x - 22 = 26

6x = 26 + 22

6x = 48

x = 48/6

x = 8

Put 8 for x in equation AD, then y = 8 - 2 = 6

coordinates of the orthocenter = (8, 6)

7 0
3 years ago
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