The answer is (y-8)(y-9). Is an explanation needed?
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Solution: The partial products of
are 800, 320, 40, 16 and the value of
is 1176.
Explanation:
To find the partial product of two numbers, first we write the both numbers as the sum of place values of the digits. Multiply each the place value of first number with the place value of second number.
![42\times28](https://tex.z-dn.net/?f=42%5Ctimes28)
![(40+2)\times(20+8)](https://tex.z-dn.net/?f=%2840%2B2%29%5Ctimes%2820%2B8%29)
![40\times 20+40\times 8+2\times 20+2\times 8](https://tex.z-dn.net/?f=40%5Ctimes%2020%2B40%5Ctimes%208%2B2%5Ctimes%2020%2B2%5Ctimes%208)
Multiply each pair individually.
![40\times 20=800](https://tex.z-dn.net/?f=40%5Ctimes%2020%3D800)
![40\times 8=320](https://tex.z-dn.net/?f=40%5Ctimes%208%3D320)
![2\times 20=40](https://tex.z-dn.net/?f=2%5Ctimes%2020%3D40)
![2\times 8=16](https://tex.z-dn.net/?f=2%5Ctimes%208%3D16)
The above values are partial product.
![800+320+40+16=1176](https://tex.z-dn.net/?f=800%2B320%2B40%2B16%3D1176)
Therefore, the partial products of
are 800, 320, 40, 16 and the value of
is 1176.
1 = 6
3-2(2-1)=2+4
3-2(1)=6
3-2=6
1=6
We can plug in the values of this point to find b
-4 = 17 (3) +b
We will multiply 17 times 3
-4 = 51 + b
We then subtract by 51 on both sides
-55 = b
So the full equation will be
y = 17x - 55