Question

Find x special right triangle

Answer 1

Answer:

$\sin(45 ) = y \div 11 \sqrt{6}$

$\frac{1}{ \sqrt{2} } = \frac{y}{11 \sqrt{6} } \\ \\ y = \frac{11 \sqrt{6} }{ \sqrt{2} } \\ y = 11 \sqrt{3}$

$\tan(60) = \frac{x }{11 \sqrt{3} } \\ \\ \sqrt{3} = \frac{x}{11 \sqrt{3} } \\ x = \sqrt{3} \times 11 \sqrt{3} \\ x = 33$