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xenn [34]
3 years ago
5

What is -34 1/2 - 5 1/2

Mathematics
2 answers:
11111nata11111 [884]3 years ago
8 0

Answer is -40 two negatives stay negative because they are not multiplying and then just add the 1/2s together to get to -40

Verizon [17]3 years ago
3 0

The answer is -40 because if you get rid of the negative sign and add instead of subtract... you get 40 so its like adding in the opposite direction.

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3 years ago
What are the orders of 3,7,9,11,13,17 and 19(mod20)?does 20 have primitive roots?
bezimeni [28]
3\equiv3\mod{20}
3^2\equiv9\mod{20}
3^3\equiv27\equiv7\mod{20}
3^4\equiv3\cdot3^3\equiv3\cdot7\equiv21\equiv1\mod{20}

7\equiv7\mod{20}
7^2\equiv49\equiv9\mod{20}
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9\equiv9\mod{20}
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11\equiv11\mod{20}
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13\equiv-7\equiv13\mod{20}
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13^4\equiv13\cdot13^3\equiv(-7)(-3)\equiv21\equiv1\mod{20}

17\equiv-3\equiv17\mod{20}
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17^3\equiv(-3)^3\equiv-27\equiv3\mod{20}
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19\equiv-1\equiv19\mod{20}
19^2\equiv19(-1)\equiv-19\equiv1\mod{20}

Generally speaking, a number x coprime to n will be a primitive root of n if we have x^n\equiv x\mod{n}, or x^{n-1}\equiv1\mod{n}. In other words, if x is of order n-1 modulo n, then x is a primitive root of n.

Since none of these numbers has order 19, it follows that 20 does not have any primitive roots.
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