Question

A family has three children. Using b to stand for a boy and g for girl give the following.(To indicate that the first child is a boy, the second child is a boy, and the third child is a girl enter bbg. Enter your answers as a comma-separated list.). Let the event E that the family has exactly two boys.
a) Find the probability p(E)
b) Find the odd o(E) Part a): [Select ] Part b): ISelect ) ?

Answer 1

Answer:

3/8 and 3/5

Step-by-step explanation:

Given that a family has three children. Using b to stand for a boy and g for girl give the following we can write sample space for a family having three children as

(bbb, bbg, bgg, bgb, gbb, gbg, ggb, ggg)

E - exactly two boys

Sample space count = 8

Exactly two boys count = 3

a) p(E) = $\frac{3}{8}$

b) odds for E is probability/1-probability

= $\frac{3}{5}$