What is the solutions set

99 Point question - Consider the graph of f(x) below. (See attachment)

Alecsey [184]

A linear function is a straight line, so that's clearly not it

A quadratic function has one point where is switches from going up to going down (or down to up), but this has two, so that's not it.

A cubic function has 2 points where it goes from down to up or up to down, so this may just work.

An exponential function has a constant to the power of something, so it's either staying constantly up or down after 0 or jumping up and down with every x value, which it isn't doing.

Logarithmic functions are similar to exponential functions in that it usually stays either going up or down the whole time.

Using our definitions, a cubic function is the only one that fits

6 0

4 years ago

Read 2 more answers

Minimum Average Cost

Dahasolnce [82]

Answer:

a) $\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

b) $\bar{C}(x)=5.81$

Step-by-step explanation:

Given that

C = 100 + 25 x - 120 ln x ,x ≥ 1.

The average cost function given as

$\bar{C}(x)=\dfrac{C(x)}{x}$

$\bar{C}(x)=\dfrac{100 + 25 x - 120 \ln x}{x}$

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx{x}$

Therefore

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

To find average minimum cost

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

$\dfrac{d\bar{C}(x)}{dx} = -\dfrac{100}{x^2} +0-120\times \dfrac{1-lnx}{x^2}$

$0 = -\dfrac{100}{x^2} +0- 120\times \dfrac{1-lnx}{x^2}$

100 + 120 (1-lnx) = 0

$lnx=\dfrac{220}{120}$

ln x =1.833

$x=e^{1.833}$

x=6.25

$\bar{C}(x)=\dfrac{100}{6.25}+25-120\dfrac{ln6.25}{6.25}$

$\bar{C}(x)=5.81$

6 0

4 years ago

Any thoughts im really confused on it

Brilliant_brown [7]

He made a mistake on step 2, because he already flipped the fraction 5/8 to 8/5, then hi flipped it back to 5/8, hope this helps.

4 0

3 years ago

Answer plz i need help

AURORKA [14]

Answer:

The expression for Annika is $ 4x and Chris is $ (x + 10).

Step-by-step explanation:

Given that Annika has 4 times more than Bob and Chris has $10 more than Bob. So the expressions will be :

Annika = 4 × x = 4x

Chris = 10 + x

3 0

3 years ago

Read 2 more answers

A national manufacturer of ball bearings is experimenting with two different processes for producing precision ball bearings. It

lapo4ka [179]

Answer:

A. As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

B. t=-3.144

C. The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

D. P-value = 0.004

E. Reject H0

F. The probability of making a Type I error is equal to the significance level: P(Type I error) = 0.05.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the two processes yield different average errors.

As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

being μ1: average error for Process A and μ2: average error fo Process B.

The significance level is 0.05.

The sample 1, of size n1=12 has a mean of 2 and a standard deviation of 1.

The sample 1, of size n1=14 has a mean of 3 and a standard deviation of 0.5.

The difference between sample means is Md=-1.

$M_d=M_1-M_2=2-3=-1$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1^2}{12}+\dfrac{0.5^2}{14}}\\\\\\s_{M_d}=\sqrt{0.083+0.018}=\sqrt{0.101}=0.318$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-1-0}{0.318}=\dfrac{-1}{0.318}=-3.144$

The degrees of freedom for this test are:

$df=n_1+n_2-1=12+14-2=24$

The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

This test is a two-tailed test, with 24 degrees of freedom and t=-3.144, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t$

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the two processes yield different average errors.

5 0

3 years ago