The variation from x to y is an illustration of a direct variation
The value of x when y = 2 is -19/7
<h3>How to determine the value of x?</h3>
The variation is a direct variation.
So, we have:
x = ky
Where k represents the constant of variation
Make k the subject
k = x/y
This gives
x1/y1 = x2/y2
So, we have:
-19/14 = x/2
Multiply both sides by 2
x = -19/14 * 2
Evaluate
x = -19/7
Hence, the value of x when y = 2 is -19/7
Read more about direct variation at:
brainly.com/question/6499629
So you've got a cartesian plane, right? There are two coordinates here. Plot the first one ((3.4)) first. the '3' is on the x axis and the '4' is on the y axis. Go 3 across until you get to 3. and then go 4 up. Put a dot there.
Next, also plot the second one. To do this, go to 3 on the x axis, and then go down until you get to -7 on the y axis. Plot your point with a dot. Then, join the dots up, and hopefully, it'll be a linear relationship!
Use the midpoint formula and solve. work pictured below
Answer:
The probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:

The standard deviation of this sampling distribution of sample proportion is:

The information provided is:
<em>p</em> = 0.60
<em>n</em> = 100
As <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportions.
The distribution of sample proportion is
.
Compute the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% as follows:


Thus, the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.
Answer:
The distance between the two points is 7 units