B i think.. the product kinda gives it off to me but i’m not sure
The answer is b I hope this helps
Answer:
Lower confidence limit = 20.191
Step-by-step explanation:
Sample mean; x' = 22
Sample standard deviation; s = 5.5
Sample size; n = 50
Confidence interval = 99%
Since sample size > 30, we will use the formula;
CI = x' ± zs/√n
Where;
x' is sample mean
s is sample standard deviation
n is sample size
z is z-value of the confidence interval
From the table attached, z for 99% = 2.3263
Thus;
CI = 22 ± (2.3263 × 5.5)/√50
CI = 22 ± 1.809
CI = 23.809 or 20.191
Lower confidence limit = 20.191
Answer:
The answer is 3.6
Step-by-step explanation:
Step one:
Singer A is offering his services for an initial $95 in addition to $12.95 per hour
let the number of hours be x and the total charge be y
the expression for the total for singer A is
y=12.95x+95----------2
Singer B is offering her services for an initial $99 in addition to $11.85 per hour
let the number of hours be x and the total charge be y
the expression for the total for singer A is
y=11.85x+99----------2
Step two:
Equating 1 and 2 we have
12.95x+95=11.85x+99
collect liker terms
12.95x-11.85x=99-95
1.1x=4
divide both sides by 1.1
x= 4/1.1
x=3.63
to the nearest tenth it is 3.6
Answer:
A, 2/5
Step-by-step explanation:
8 + 10 + 9 + 6 + 7 = 40
9 + 7 = 16
16/40
divide both sides by 8 (common factor)
2/5
