Sure this question comes with a set of answer choices.
Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.
Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant. This is, the equation has the form:
y = a(x + 4)(x - 2)
Now, since the point (6,10) belongs to the parabola, you can replace those coordintates to get:
10 = a (6 + 4) (6 - 2)
Therefore, any of these equivalent equations can be solved to determine the value of a:
10 = a 6 + 40) (6 -2)
10 = a (10)(4)
10 = 40a
Answer:
(x+3)^2 +(y-5)^2 = 36
Step-by-step explanation:
We can write the equation of a circle as
(x-h)^2 +(y-k)^2 = r^2 where (h,k) is the center and r is the radius
(x- -3)^2 +(y-5)^2 = 6^2
(x+3)^2 +(y-5)^2 = 36
Answer:
The final solution is all the values that make (x-6)(x+5)=0 true.
x=6, -5
Answer:
x=ym−4
Step-by-step explanation:
y=(4+x)m
Here we have one equation with three unknowns. This cannot be "solved". We can only express one variable in terms of the other two.
Let's isolate x.
Divide through by m
ym=4+x
x=ym−4
(I really hope this helps)
