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Lilit [14]
3 years ago
10

Sine (StartFraction pi Over 6 EndFraction) =

Mathematics
1 answer:
olasank [31]3 years ago
8 0

Answer:

53w

Step-by-step explanation:

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What is -13/25 as a decimal
pickupchik [31]
If you would like to know what is - 13/25 as a decimal, you can calculate this using the following step:

- 13/25 = - (4*13)/100 = - 52/100 = - 0.52

Result: - 13/25 as a decimal is - 0.52.
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Please help)Simplify: (r – 7)(r + 7)
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Im pretty sure the answer is

C) r^2 - 49

Step-by-step explanation:

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You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 35 bacteria reveals a sampl
pickupchik [31]

Answer: Sample size would be 296.

Step-by-step explanation:

Since we have given that

Standard deviation = 4.8 hours

Margin of error = 0.65 hours

At 98% level of confidence, z = 2.33

So, It becomes,

0.65=z\times \dfrac{\sigma}{\sqrt{n}}\\\\0.65=2.33\times \dfrac{4.8}{\sqrt{n}}\\\\\dfrac{2.33\times 4.8}{0.65}=\sqrt{n}\\\\n=(\dfrac{11.184}{0.65})^2\\\\n=17.206^2\\\\n=296.051

Hence, sample size would be 296.

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3 years ago
What is the test that you can do to tell if a graph represents a function?
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B. the vertical line test
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Can someone help me with this
mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

5 0
2 years ago
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