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Goshia [24]
4 years ago
12

What can increase the rate that lactic acid is removed from the muscles?

Biology
1 answer:
Pavlova-9 [17]4 years ago
5 0

The rate at which lactic acid is removed from the muscles can be increased by DRINKING WATER

HOW LACTIC ACID FORMS IN MUSCLES:

  • Lactic acid is produced in the muscle cells when there is lac of or insufficient oxygen to perform aerobic respiration. During vigorous exercise e.g. running, oxygen is used up faster, hence, causing cells to switch to anaerobic respiration (fermentation) leading to the build up of lactic acid.

WAY TO HELP THE BODY GET RID OF LACTIC ACID IN MUSCLE CELLS:

  • Lactic acid buildup often comes with pain and soreness in the muscles. However, the rate of removal of lactic acid in the muscle cells can be increased by staying hydrated (drinking water) prior to, during and post exercise.

The rate at which lactic acid is removed from the muscles can be increased by DRINKING WATER.

Learn more at: brainly.com/question/815992

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What is the removal of a short section of stem called?
Alex

Answer:

Cuttings: Pieces of stem or root cut from a plant to produce new plants

Herbaceous cutting: type of cutting taken from plants that never form a woody stem

Leaf cutting :a cutting that includes a short section of stem with a leaf attached

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4 years ago
Viral STIs are not curable and can only be controlled with medications.<br> a. True<br> b. False
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8 0
3 years ago
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What is biomass?
ss7ja [257]

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Renewable energy captured through using the heat of the Earth

Explanation:

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4 years ago
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How are marsh grasses adapted to the dry regions in Texas
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6 0
4 years ago
In a population of gerbils ,long hair is completely dominant over short hair .if 18percent of the population has short hair , ca
oee [108]

Answer: 49%

Explanation:

* long hair = P

* shirt hair = q using the Hardy-Weinberg equation for genotypic frequencies

* p^2 + 2pq + q^2 =1

*first use the equation to solve for the known value 18% hh

.18 = q^2

Square root .18 = q

So q = .42

* plug this allelic frequency in to p+q = 1

Which will give you the frequency of dominant alleles

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Then just plug the P and q values found into the portion of the equation for heterozygous offspring.

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Which is .49 or 49%

The entire population should be 33% homozygous dominant 49% heterozygous and 18% homozygous recessive.

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