Dy/dx = y cos x
y = Ae^sin(x)
y(0) = Ae^sin(0) = A = 3
A = 3
Therefore, y = 3e^(sinx)
Answer:
The equation of the sraight line 3x- y+ 6 =0
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the gradient of the function
|gradf| = 3 and point (-1,3)
Given that the slope of the line
m = 3
The equation of the straight line passing through the point(-1,3) and slope m =3
y-3 = 3(x-(-1))
y-3 = 3x+3
3x +3-y+3=0
3x- y+ 6 =0
<u><em>Final answer:-</em></u>
The equation of the sraight line 3x- y+ 6 =0
<u><em></em></u>
Answer:
1.9°C
Step-by-step explanation:
Let X be the temperature at noon and -2.5°C be the current temperature after the drop.
-We calculate temperature at noon as:
Hence, the temperature at noon was 1.9°C
Answer:
I think it's A
Step-by-step explanation:
Answer:
top is -2,4 and bottom is 3,-2 ??
hope that what u need
Step-by-step explanation:
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