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Katarina [22]
2 years ago
9

Find all of the missing angles... Just find as many as you can please anything will help.

Mathematics
2 answers:
Daniel [21]2 years ago
5 0
B=144....................................
Anastasy [175]2 years ago
4 0
A = 180 - 143 = 37
b = 143
c = a = 37
e = a = 37
f = 90 - 37 = 53
d = 180 - 85 - 37 = 58
g = 48
h = 180 -48 -48 = 84
k = 180 -84 = 96
m = 180 - 58 - 96 = 26
p = 180 - 26 - 85 = 69
r = 180 -69 = 111
s = p = 69



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nordsb [41]

My best guess would be 720.


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Hope this helps! If its not right please inform me on what I did wrong!

3 0
3 years ago
Express the complex number in trigonometric form. -6 + 6 square root of 3 i ?
bagirrra123 [75]
\bf \begin{array}{clclll}
-6&+&6\sqrt{3}\ i\\
\uparrow &&\uparrow \\
a&&b
\end{array}\qquad 
\begin{cases}
r=\sqrt{a^2+b^2}\\
\theta =tan^{-1}\left( \frac{b}{a} \right)
\end{cases}\qquad r[cos(\theta )+i\ sin(\theta )]\\\\
-------------------------------\\\\

\bf r=\sqrt{(-6)^2+(6\sqrt{3})^2}\implies r=\sqrt{36+(6^2\cdot 3)}\implies r=\sqrt{144}
\\\\\\
r=12\leftarrow 
\\\\\\
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\begin{cases}
\frac{2\pi }{3}\leftarrow \\
\frac{5\pi }{3}
\end{cases}

now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.

thus         \bf 12\left[cos\left( \frac{2\pi }{3} \right) +i\ sin\left( \frac{2\pi }{3} \right) \right]
5 0
3 years ago
Geometry Need help/........
vekshin1
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