2x-6y=24
-5x+6y=-6
2x=24+6y
2x-24=6y
-5x+6y=-6
6y=5x-6
2x-24=5x-6
-24+6=5x-2x
-18=3x
-18/3=x
x=-6
2x-6y=24
2(-6)-6y=24
-12-6y=24
-6y=24+12
-6y=36
y=36/-6
y=-6
If we were to foil
after experieence
we know
ax²+bx+c=0
and
in form
(ax+b)(cx+d)=0
if we expand it, we get
acx²+bcx+adx+bd=0
or
(ac)x²+(bc+ad)x+(bd)=0
compare to
ax²+bx+c=0
we notice that the middle terms (x terms) are
b=(bc+ad)
so
in form
(2x-1)(1x+5)
b=bc+ad=(-1*1+2*5)=-1+10=9
b=9
or you could just expand it
Refer to the attached image.
As we can observe ABCD is a square, whose corners that is A,B,C and D lie on the circle.
The diameter AC = 0.35 meter.
We have to find the side of square.
Let the measure of side of a square be 'l' meter
In triangle ABC,
By Pythagoras theorem, we get





So, l = 0.25 meter
Therefore, the measure of side of the square is 0.25 meter.
Answer:
B, C
Step-by-step explanation:
graph the following lines with negative slopes and compare:
y = -x + 1
y = -20x + 2
Answer:
i think its c
Step-by-step explanation: