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ladessa [460]
2 years ago
12

The expression 2(l + w) is used to calculate the perimeter of a rectangle, where l is length and w is width. If the length is 2/

7 unit and the width is 3/7 unit, what is the perimeter of the rectangle in units?
Mathematics
2 answers:
Pepsi [2]2 years ago
7 0

Answeryall are dumb like this is clearly not a option :(

Step-by-step explanation:

xeze [42]2 years ago
6 0

Answer:

P = 10/7 units

Step-by-step explanation:

Answer:

w ≥ 6

l ≥ 11

Step-by-step explanation:

The perimeter of a rectangle is equal to P = 2(l+w) where l=length and w=width. Here the length is 2/7. This means the width is 3/7. Substitute l=2/7 and w=3/7 into the perimeter equation. Then solve for P.

P = 2(\frac{2}{7} +\frac{3}{7} )\\\\P = 2(\frac{5}{7})\\\\P = \frac{10}{7}

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ziro4ka [17]

Answer:

x ≈ 28.8°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin x = \frac{opposite}{hypotenuse} = \frac{AB}{AC} = \frac{3.9}{8.1} , then

x = sin^{-1} (\frac{3.9}{8.1} ) ≈ 28.8° ( to the nearest tenth )

3 0
2 years ago
Two ocean beaches are being affected by erosion. The table shows the width, in feet, of each beach at high tide measured where 1
sergeinik [125]

Answer:

10 and 11

Step-by-step explanation:

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2 years ago
The length of an alligator in a zoo is 14 5/6 feet.The everglades national parks list the longest alligator ever reocord in flor
astraxan [27]

Answer:

The difference in the lengths of the two alligators = 3

Step-by-step explanation:

First, let us make the lengths improper fractions, then we will find the difference from there.

Alligator 1:

Length = 14\frac{5}{12} = \frac{173}{12}

To convert to improper fraction, multiply the denominator by the whole number, and then add the denominator [(12 × 14) + 5]

Alligator 2:

Length = 17\frac{5}{12} = \frac{209}{12}

Now Let us find the difference between the lengths:

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Solve for xxx.<br> x=x=x, equals
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Answer: The answer is of course, 3.

Step-by-step explanation:

7 0
2 years ago
In a certain Algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. There are 4 students who p
Flauer [41]

Answer:

\frac{4}{5}

Step-by-step explanation:

Given: There are 2 classes of 25 students.

            13 play basketball

            11 play baseball.

            4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

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taking LCD as 25 to solve.

⇒P(a∪b)= \frac{13\times 1+11\times 1-4\times 1}{25} = \frac{20}{25}

∴ P(a∪b)= \frac{4}{5}

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is \frac{4}{5}.

6 0
3 years ago
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