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Inessa [10]
3 years ago
8

Help! Which expression is equivalent? On edge

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer: Choice B

x^{1/8}y^{8}

======================================================

Explanation:

The two rules we use are

(a*b)^c = a^c*b^c

(a^b)^c = a^{b*c}

When applying the first rule to the expression your teacher gave you, we can say that:

\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}

Then applying the second rule lets us say

\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}

Therefore,

\left(x^{1/4}y^{16}\right)^{1/2}  = x^{1/8}y^{8}

-------------

In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

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Whats the answer (10 points)
expeople1 [14]

Answer:

x=79 degrees y=22degrees

Step-by-step explanation:

you see it has 2 equal sides, so the triangle is an isosceles triangle. If the triangle is isosceles, then its 2 base angles are equal, that is, x = 79 according to the triangle property, the 3 angles add up to 180 degrees, so you take 180 degrees minus 2 * 79 degrees you get a y angle equal to 22 degrees

3 0
2 years ago
On this number line, 1 tick mark represents 4 units. Find the length of segment AB. A. 32 units B. 36 units C. 44 units D. 48 un
mylen [45]

Number lines are used to represent numbers at regular intervals

The length of segment AB is 44 units

<h3>How to determine the length of AB</h3>

From the question, we have:

AB = 11 tick marks

Given that 1 tick mark represents 4 units

Then, we have:

AB = 11 * 4

Evaluate the product

AB = 44 units

Hence, the length of segment AB is 44 units

Read more about number lines at:

brainly.com/question/10851163

6 0
2 years ago
1)Which of the ordered pairs is NOT a
Butoxors [25]

Answer:

a) {(3,3),(3,4),(4,5),(4,6)}

Step-by-step explanation:

Given

(a) to (d)

Required

Which is not a function

A relation is represented as:

\{(x_1,y_1),(x_1,y_1),(x_2,y_2),...............(x_0,y_0)\}

For the relation t be a relation, then:

x_i \ne x_jwhere i \ne j

This means that none of the x values must be related.

The first relation has 3 repeated as its value of . Hence, (a) is a relation

8 0
3 years ago
Find both the number of combinations and the number of permutations for the given number of objects.
Nikitich [7]

Answer:

First, if we have a set of K elements, such that are ordered as:

{x₁, x₂, ...}

The total number of permutations for the K elements can be found in the next way.

For the first element in the set, we have K options.

For the second element in the set, we have (K - 1) options (because we already choose one)

For the third element we have (K - 2) options, and so on.

The total number of permutation is equal to the product between the numbers of options for each position's element, then the number of permutations for K elements is:

permutations = K*(K - 1)*(K - 2)*....*2*1 = K!

Now suppose that we have a set of N elements, and we want to make groups of K elements.

The total number of different combinations of K elements is given by the equation:

C(N, K) = \frac{N!}{(N - K)!*K!}

In this case we have 15 objects (then  N = 15) and we take 7 at the time (Then K = 7)

Where we need to take in account the number of combinations and also the permutations for each combination.

Then the total number of different sets is:

C(15*7)*7!

First, the total number of combinations will be:

C(15,7) = \frac{15!}{(15 - 7)!7!} = \frac{15!}{8!*7!}  = \frac{15*14*13*12*11*10*9}{7*6*5*4*3*2*1}  = 6,435

So we have 6,436 combinations, and each one of these combinations has 7! permutations.

permutations = 7! = 7*6*5*4*3*2*1 = 5,040

if we combine these we get:

Combinations*Permutations = 6,435*5,040 = 32,432,400

5 0
3 years ago
Pls answer both the question its urgent
Ilya [14]

Answer:

not sure but I think it is this

8 0
2 years ago
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