Answer:
y= -x(x+2)(x-1)².
Step-by-step explanation:
the graph and equation is in the attached picture.
The zeros of function y are: -2; 0 and 1 - they help to determine the required equation.
Answer:
x = 4
Step-by-step explanation:
Find 8 on the y-axis. Draw a horizontal line through y =8. Determine the x value for which the graph intersects this horizontal line y = 8. It is x = 4
Answer:
q= -ck+dp/
-k+d
Step-by-step explanation:
Step 1:
Multiply both sides by p.
dp=ck−kq+pq
Step 2:
Flip the equation.
ck−kq+pq=dp
Step 3:
Add -ck to both sides.
−kq+pq=−ck+dp
Step 4:
Factor out variable q.
q(−k+p)=−ck+dp
Step 5:
Divide both sides by -k+p.
q= -ck+dp/
-k+d
Sorry if it's all letters and u needed numbers.
Polynomials are equations that uses variables and several terms
The polynomial in standard form is f(x) = x^2 - x -20
<h3>How to determine the polynomial</h3>
The polynomial has 2 zeros.
So, the form of the polynomial is:
f(x) = a(x - x1)(x - x2)
The zeros of the polynomial are 5 and -4.
So, the equation becomes
f(x) = a(x - 5)(x + 4)
The value of a = 1.
So, we have;
f(x) = 1(x - 5)(x + 4)
This gives
f(x) = (x - 5)(x + 4)
Expand
f(x) = x^2 - x -20
Hence, the polynomial in standard form is f(x) = x^2 - x -20
Read more about polynomials at:
brainly.com/question/2833285
Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ = 
≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM = 
≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ
