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1 answer:
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To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!
- Side 3 metre
<em>Thus, The area of 1st square is 9m²...</em>
- The area of second square will be also 9m², because the sides of both squares are equal.
- Length = 6m
- Breadth = 7+3=10m
<em>Thus, The area of rectangle is 30m²....</em>
- Now, Add area of all the figures to get the total area.
Answer:
Step-by-step explanation:
We know that the graph passes through the point , since the line crosses the X-axis at
, so that means our equation has
in it. The graph also passes through the point
, so the equation also has
in it.
This narrows it down to options C and D.
When a graph "bounces" off the X-axis at a point, like it does at , this is called a "double zero", meaning two factors of the equation equal zero. This means that the graph has
, leaving us with option D.
Alright assuming they mean total surface area since they didn't say lateral the equation to follow would be S= Ph + 2B
Start with P:
P stands for perimeter, so add up all the edges on one face of the cube.
Then your equation becomes
S= 68×h + 2B
h=height and that's obviously 17
so, S= 68×17 +2B
Now to find B. This is pretty easy. All you need to do is take 17×17 because you're finding the area of the base. This equals 289.
Finally this leaves us with the equation
S= 68×17+2×289
From there on you just solve it out.
This would leave you with 1734.
Start with P:
P stands for perimeter, so add up all the edges on one face of the cube.
Then your equation becomes
S= 68×h + 2B
h=height and that's obviously 17
so, S= 68×17 +2B
Now to find B. This is pretty easy. All you need to do is take 17×17 because you're finding the area of the base. This equals 289.
Finally this leaves us with the equation
S= 68×17+2×289
From there on you just solve it out.
This would leave you with 1734.