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tia_tia [17]
3 years ago
14

Is (3,-3)(3,−3)left parenthesis, 3, comma, minus, 3, right parenthesis a solution of the graphed system of inequalities?

Mathematics
1 answer:
defon3 years ago
7 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:

No.

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

  • If we mark the point at (3, -3), the we can tell that the point does not lie in any shaded region.
  • This means that it is NOT a solution to the system.

See the graph attached.

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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Alejandro weighs 37 pounds and sits on a seasaw 2 feet away from its center. If his brother marco sits on the seasaw 3 feet away
MA_775_DIABLO [31]
A) 3x2=6+37=43

B) 43 rounding to greatest place value=40

Marco Weighs 40 Pounds.Its Because 3x4=6+37=43.Last When You Round 43 You Have To Round To The Greatest Place Value.So When You Round The 3 Is Low So You Change It To 0 And The 4 Stays The Same

3 0
4 years ago
1+4x=-5+7x what does x equal<br>​
katrin [286]

Answer:

x = 2

Step-by-step explanation:

Given

1 + 4x = - 5 + 7x ( subtract 7x from both sides )

1 - 3x = - 5 ( subtract 1 from both sides )

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8 0
3 years ago
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A bag contains 6 red balls and 5 black balls . Two balls are picked , one after the other . Find the probability that :
Kaylis [27]

Answer:

<u>There are:</u>

  • 6 red balls - R
  • 5 black balls - B
  • Total number = 11 balls
<h3>A. Without replacement</h3>

i. <u>Two blacks </u>

  • P(BB) = 5/11*4/10 = 2/11

ii. <u>The first is black</u>

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or, alternatively

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iii. <u>Both are of same colour</u>

  • P(BB or RR) = 2/11 + 6/11*5/10 = 2/11 + 3/11 = 5/11
<h3>B. With replacement</h3>

i. <u>Two blacks </u>

  • P(BB) = 5/11*5/11 = 25/121

ii. <u>The first is black</u>

  • P(B) = 5/11

or alternatively

  • P(BR or BB) = 5/11*6/11 + 25/121 = 30/121 + 25/121 = 55/121 = 5/11

iii. <u>Both are of same colour</u>

  • P(BB or RR) = 5/11*5/11 + 6/11*6/11 = 25/121 + 36/121 = 61/121
7 0
3 years ago
Find the area of a regular hexagon with an apothem 17.3 miles long and a side 20 miles long
Zinaida [17]
The area of a hexagon is \frac{3 \sqrt{3} }{2} a^{2} where a = one side

\frac{3 \sqrt{3} }{2} 20^{2}

\frac{3*200 \sqrt{3} }{2}

\frac{600 \sqrt{3} }{2}

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4 0
3 years ago
Solve for x:<br> -3x +5 = 17
valentina_108 [34]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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